La suma de dos números es 27

Mathematics

1 answer:

Olin [163]3 years ago

7 0

Answer:

Step-by-step explanation:

2x = 27

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An engineer deposits $2,000 per month for four years at a rate of 24% per year, compounded semi-annually. How much will he be ab

Alex17521 [72]

The amount of money he will be able to withdraw after 10 years after his last deposit is $926,400.

<h3>Compound interest</h3>

Principal, P = $2,000 × 12 × 4

= $96,000

Time, t = 10 years
Interest rate, r = 24% = 0.24
Number of periods, n = 2

A = P(1 + r/n)^nt

= $96,000( 1 + 0.24/2)^(2×10)

= 96,000 (1 + 0.12)^20

= 96,000(1.12)^20

= 96,000(9.65)

= $926,400

Therefore, the amount of money he will be able to withdraw after 10 years after his last deposit is $926,400

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2 years ago

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,