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Gwar [14]
2 years ago
15

Does anyone know how to answer 18 - 16/5

Mathematics
2 answers:
Anarel [89]2 years ago
8 0
18- 16/5 = 14.8

If that’s what you’re asking
allsm [11]2 years ago
8 0

Answer:

5.8 or 29/5

Step-by-step explanation:

you have a typo mistake it's 61 not 16

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gulaghasi [49]

Answer:

6x^3+6y^3+10

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Examine the table below showing the merchandising sales and answer the questions that follow.
-BARSIC- [3]

Answer:

The mean amount spent = £14.80

The modal product is hoodies.

Step-by-step explanation:

Here

25 T shirts each costing £10 were purchased

Amount spent on T shirts = 25 × 10 = £250

30 key ring of £5 were purchased

Amount spent on key ring = 30 × 5 = £150

40 Hoodies for £25 each

Amount spent on Hoodies = 40 × 25 =£1000

30 CD's for £15 each

Amount spent on CD's = 30 ×15 = £450

Total amount spent = 250 +150 + 1000 + 450 = £1850

Total items purchased = 25 + 30 + 40 + 30 = 125

Mean amount spent = \frac{1850}{125}= 14.80

The modal product is Hoodies as the maximum number of hoodies were purchased.


6 0
3 years ago
In college​ basketball, a shot made from beyond a designated arc radiating about 20 ft from the basket is worth three points ins
denis-greek [22]

Answer:

a) By the Central Limit Theorem, the distribution would be approximately normal, with mean \mu = 0.45 and standard deviation s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497

b) 4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered surprising, so yes, it would be surprising for him to make only 25 of these shots.

Step-by-step explanation:

To solve this question, we are going to need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For proportions, we have that the mean is \mu = p and the standard deviation is s = \sqrt{\frac{p(1-p)}{n}}

In this problem, we have that:

p = 0.45, n = 100

a)By the Central Limit Theorem, the distribution would be approximately normal, with mean \mu = 0.45 and standard deviation s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497

b)This is Z when X = 0.25.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.25 – 0.45}{0.0497}

Z = -4.02

4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered

surprising, so yes, it would be surprising for him to make only 25 of these shots.

3 0
3 years ago
If T equals 1 / r + 1 / s equals r + S over RS, then what is 1 / T in terms of R&S?
Thepotemich [5.8K]
T=\dfrac{1}{r}+\dfrac{1}{s}\\\\T=\dfrac{1\cdot s}{r\cdor s}+\dfrac{1\cdot r}{r\cdot s}\\\\T=\dfrac{s}{rs}+\dfrac{r}{rs}\\\\T=\dfrac{s+r}{rs}\to\dfrac{1}{T}=\dfrac{rs}{s+r}
7 0
3 years ago
Simplify the expression given below.<br><br> x+2/ 4x^{2} +5x+1 *4x+1/2x-4[/tex]
VashaNatasha [74]

Answer:

pls write understandably

7 0
3 years ago
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