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artcher [175]
3 years ago
7

A cars value starts at $32,000. After 1 year, it is worth $27,200. What is the decay factor?

Mathematics
1 answer:
notka56 [123]3 years ago
7 0

Answer:

15% × 7 = 1.05

32,000 - 1.05 = 31,998.95

31,998.95 ‐‐‐‐‐> 31,999

$31,999

(If you don't need to simplify, the answer would be $31,998.95, but I did it just incase you do)

Step-by-step explanation:

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Answer:

First Image:         Option D

Second Image:   Option D

Third Image:       Option C

Fourth Image:     Option B

Fifth Image:         Option B

Step-by-step explanation:

<u>First Image:</u>

  • Supplementary angles is two angles whose sum is 180 degrees (straight line)
  • 180 - 47 = 133°
  • ? is an obtuse angle is any angle greater than 90° which checks the answer

<u>Second Image:</u>

  • A triangle angles adds up to 180°
  • Two angles are already given
  • 72 + 45 + ? = 180° → 117 + ? = 180° → ? = 63°
  • ? is an acute angle is an angle that measures between 90° and 0°

<u>Third Image:</u>

  • Supplementary angles is two angles whose sum is 180 degrees (straight line)
  • 180 - 110 = 70°
  • ? is an acute angle is an angle that measures between 90° and 0°

<u>Fourth Image:</u>

  • Supplementary angles is two angles whose sum is 180 degrees (straight line)
  • 180 - 120 = 60°
  • we are shown a right angle which = 90°
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  • 180 - 90 - 60 = 30
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<u>Fifth Image:</u>

  • Supplementary angles is two angles whose sum is 180 degrees (straight line)
  • 180 - 85 = 95°
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Learn more about Triangles here: brainly.com/question/4186813

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2 years ago
Choose the rate of change (slope) to match the line.
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8 0
3 years ago
I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.
elena-14-01-66 [18.8K]

Hello,

m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\

cos(30^o)=\dfrac{\sqrt{3} }{2} \\

In the triangle ABC,

cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\

sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}

In the triangle ACB,

cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\

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