Another question of the homework
1 answer:
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Answer:
Step-by-step explanation:
Let's solve this using our formula for exponential functions:
where a is the initial value and b is the growth/decay rate. We will fill that equation in with 2 of the coordinates on the graph and come up with the values for both a and b. (0, 3) and (1, 6):
. Anything raised to the power of 0 is 1, so that means that
a = 3. We will use that value along with the x and y from the second coordinate to solve for b:
. b to the first is just b, so our equation is
6 = 3b and
b = 2.
Our equation then is
, the third choice down.
Answer:
Step-by-step explanation:
Given: There are 2 classes of 25 students.
13 play basketball
11 play baseball.
4 play neither of sports.
Lets assume basketball as "a" and baseball as "b".
We know, probablity dependent formula; P(a∪b)= P(a)+P(b)-p(a∩b)
As given total number of student is 25
Now, subtituting the values in the formula.
⇒P(a∪b)=
taking LCD as 25 to solve.
⇒P(a∪b)=
∴ P(a∪b)=
Hence, the probability that a student chosen randomly from the class plays both basketball and baseball is .