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bija089 [108]
3 years ago
12

F(x) = -2x, g(x)= -2x-1

Mathematics
1 answer:
GarryVolchara [31]3 years ago
4 0

Answer:

I graphed the two points on a graph in the attachment! Hope this helps! :)

Step-by-step explanation:

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If the figure is reflected over the line y=x, which rule is true
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Answer:

These reflected points represent the inverse function

Step-by-step explanation:

This is just one of the rules that are true.

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The area of a rectangular garden in square feet is x^2+35x-450. The width is (x-10) feet. What is the length of the garden?
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X^2 + 35x - 450
Factor
(x + 45)(x - 10)

(x + 45) is the length

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Write the equation in slope-intercept form (y=mx + b) for a line with a slope of 2/3 and a y-intercept of -5.
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Match its group with its percentage or mean Using
krok68 [10]

(1)

Mean length of all fish in the sample - \boxed{\sf{\red{6.2}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

=<em> 6.2</em>

(2)

Mean length of adult fish in the sample - \boxed{\sf{\red{8.75}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

=<em> 8.75</em>

(3)

Mean length of juvenile fish in the sample - \boxed{\sf{\red{4.5}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

<em>= 4.5</em>

(4)

Percentage of sample that were adult fish - \boxed{\sf{\red{40}}}

<u>Percentage</u> = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

<em>% = 40</em>

(5)

Percentage of sample that were juvenile fish - \boxed{\sf{\red{60}}}

<u>Percentage</u> = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

<em>% = </em><em>6</em><em>0</em>

(6)

Percentage of sample that were juveniles over 8 inches long - \boxed{\sf{\red{10}}}

<u>Percentage</u> = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

% = (1/10) × 100

<em>% = </em><em>1</em><em>0</em>

7 0
3 years ago
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