Answer:
y = In | cos(2x + c ) | + c
Step-by-step explanation:
y" + (y')^2 + 4 = 0
substituting u = y'
u' + u^2 + 4 = 0
hence : u' = - (u^2 + 4 )
= 1 ------- (1)
integrating both sides of the equation 1
x + c = hence u = -2 tan(2x + c )
remember u = y'
y' = -2 tan(2x + c) ------ (2)
integrating both sides of the equation 2
y = ∫
therefore Y = In | cosu | + c
y = In | cos(2x + c ) | + c
Answer:
1\7
Step-by-step explanation:
Answer:
200.96 = area of Shaded portions.
Step-by-step explanation:
Area of the 2 stars.
I don't know if you can see this or not, but the 4 quarter circles surrounding the star is found by subtracting a full small square surrounding the star
Area of 1 star = 4 * (1/4) pi * r^2
Area of 1 star = 3.14 * 4^2
Area of 1 star = 50.24
Area of both stars = 100.48
Area of the 4 semicircles at each end
The 2 semicircles at one end figure = 1 circle
The two circles gives the total area of the 4 semicircles.
Area 1 circle = pr * r^2
Area 1 circle = 3.14 * (8/2)^2
Area 1 circle = 50.24
There are 2 such circles = 100.48
Total area of both results
Total Area = 100.48 + 100.48
Total Area = 200.96
Answer:
Step-by-step explanation:
This is a right triangle problem. The reference angle is x, the side opposite the reference angle is 32, and the hypotenuse is 58. The trig ratio that relates the side opposite a reference angle to the hypotenuse is the sin. Filling in accordingly:
Because you are looking for a missing angle, you will use your 2nd button and then the sin button to see on your display:
Within the parenthesis enter the 32/58 and you'll get your angle measure. Make sure your calculator is in degree mode, not radian mode!!!