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dmitriy555 [2]
3 years ago
15

TELL ME WHERE THESE GO PLEASE?

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
3 0

<u>Answers</u>

-x + 5y = 4  ⇔ slope 1/5, y-intercept 4/5

5y - x = 15  ⇔   slope: 1/5, y-intercept: 3

2y - 3x = 7  ⇔ slope: 3/2, y-intercept: 7/2

2y = 5x + 7  ⇔ slope: 5/2, y-intercept: 7/2

<u>Explanation</u>

-x + 5y = 4

5y = x + 4

y = (1/5)x + 4/5                   slope 1/5, y-intercept 4/5


5y - x = 15

5y = x + 15

y = (1/5)x + 3                       slope: 1/5, y-intercept: 3


2y - 3x = 7

2y = 3x + 7

y = (3/2)x + 7/2                 slope: 3/2, y-intercept: 7/2


2y = 5x + 7

y = (5/2)x + 7/2              slope: 5/2, y-intercept: 7/2

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The 12th term of the arithmetic sequence is 10.5. The 18th term of this sequence is 13.5. Find the common difference and the fir
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Step-by-step explanation:

<em>use </em><em>the </em><em>formula</em><em> for</em><em> </em><em>the</em><em> </em><em>nth </em><em>term </em><em>of </em><em>an </em><em>ap </em><em>Tn=</em><em>a+</em><em>(</em><em>n-1)</em><em>d</em>

<em>T12=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>T18=</em><em>1</em><em>3</em><em>.</em><em>5</em>

<em>therefore</em><em> </em><em>come </em><em>up </em><em>with </em><em>two </em><em>equations</em>

<em>T12=</em><em>a+</em><em>(</em><em>1</em><em>2</em><em>-</em><em>1</em><em>)</em><em>d</em>

<em>1</em><em>0</em><em>.</em><em>5</em><em>=</em><em>a+</em><em>1</em><em>1</em><em>d</em><em>(</em><em>1</em><em>s</em><em>t</em><em> </em><em>equation</em><em>)</em>

<em>T18</em><em>=</em><em>a+</em><em>(</em><em>1</em><em>8</em><em>-</em><em>1</em><em>)</em><em>d</em>

<em>1</em><em>3</em><em>.</em><em>5</em><em>=</em><em>a+</em><em>1</em><em>7</em><em>d</em><em>(</em><em>2</em><em>n</em><em>d</em><em> </em><em>equation</em><em>)</em>

<em>then </em><em>solve </em><em>both </em><em>as </em><em>a </em><em>simultaneous</em><em> </em><em>equation</em>

<em>a+</em><em>1</em><em>1</em><em>d</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a+</em><em>1</em><em>7</em><em>d</em><em>=</em><em>1</em><em>3</em><em>.</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em>-6d/</em><em>-</em><em>6</em><em>=</em><em>-</em><em>3</em><em>/</em><em>-</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d=</em><em>0</em><em>.</em><em>5</em>

<em>use </em><em>one </em><em>of</em><em> the</em><em> </em><em>equations</em><em> </em><em>to </em><em>find </em><em>the </em><em>first</em><em> </em><em>term</em>

<em>a+</em><em>1</em><em>1</em><em>(</em><em>0</em><em>.</em><em>5</em><em>)</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a+</em><em>5</em><em>.</em><em>5</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>-</em><em>5</em><em>.</em><em>5</em>

<em>a=</em><em>5</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

<em>please </em><em>mark</em><em> </em><em>as </em><em>brainliest</em>

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Identify the segment bisector of XY.
Ganezh [65]

Given the image attached, the segment bisector that divides XY into two and the length of XY are as follows:

  • Segment bisector of XY = line n
  • Length of XY = 6

<em><u>Recall:</u></em>

  • A line that divides a segment into two equal parts is referred to as segment bisector.

In the diagram attached below, line n divides XY into XM and MY.

Thus, the segment bisector of XY is: line n.

<em><u>Find the value of x:</u></em>

XM = MY (congruent segments)

  • Substitute

5x + 8 = 9x + 12

  • Collect like terms and solve for x

5x + 8 = 9x + 12\\5x - 9x = -8 + 12\\\\-4x = 4\\\\x = -1

XY = XM + MY

XY = 5x + 8 + 9x + 12

  • Plug in the value of x

XY = 5(-1) + 8 + 9(-1) + 12\\\\XY = -5 + 8 -9 + 12\\\\\mathbf{XY = 6}

Therefore, given the image attached, the segment bisector that divides XY into two and the length of XY are as follows:

  • Segment bisector of XY = line n
  • Length of XY = 6

Learn more here:

brainly.com/question/19497953

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