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3 years ago

Which statement is true

Mathematics

1 answer:

anzhelika [568]3 years ago

4 0

Answer:

Its C

Step-by-step explanation:

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The area of a quarter circle is 38.465 square<br> inches. What is the quarter circle's radius?

LuckyWell [14K]

The formula for a circle's area is $A=\pi r^2$ . We are given an area of 38.465 square inches for a quarter of it.

Multiply this value by 4 to compensate for the quarter circle.

$4 \times 38.465=\pi r^2$

$153.86=\pi r^2$

Divide both sides by pi (Note: I'm using the conventional value of 3.14)

$49=r^2$

Take the positive square root of both sides

$7=r$

The radius is 7 inches. Let me know if you have any questions, thanks!

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2 years ago

What is the value of<br> 3 to the power of 2 under 3 to the power of 4

garri49 [273]

Answer: 9/81

Step-by-step explanation:

I did 3 to the second power then 3 to the fourth power. Then put them on top of each other. If the over is supposed to mean division then the answer would be 9.

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3 years ago

70 POINTSS!!!! URGETT PLS HELP!! Vectors t = −5i + 2j, u = −3i + 7j, and v = 8i + 20j are given.

LUCKY_DIMON [66]

The angle between the vectors t and u is 45°. And the vector t and vector w are orthogonal to each other.

<h3>What is a vector?</h3>

The quantity which has magnitude, direction and follows the law of vector addition is called a vector.

The vectors are given below.

t = −5i + 2j, u = −3i + 7j, and v = 8i + 20j

Part A: Then the angle between vectors t and u will be

$\cos \theta = \dfrac{\overrightarrow{a} \cdot \overrightarrow{b}}{|\overrightarrow{a}| + |\overrightarrow{b}|}$

Then we have

cos θ = [(−5i + 2j)(−3i + 7j)] / [√{(-5²) + 2²} + √{(-3)² + 7²}]

cos θ = 1 / √2

θ = 45°

Part B: c is a scalar

If $\rm \overrightarrow{\rm v} = (a, b)$ , then $\rm c\overrightarrow{\rm v} = c(ca, cb)$

Let c = 2, then we have

$\overrightarrow{\rm w} = c\overrightarrow{v}\\\\\overrightarrow{\rm w} = (2*8, 2*20)\\\\\overrightarrow{\rm w} = (16, 40)$

Part C: Use the dot product to determine if t and w are parallel or orthogonal.

$\overrightarrow{\rm t} \cdot \overrightarrow{\rm w} = (-5, 2)(16, 40)\\\\ \overrightarrow{\rm t} \cdot \overrightarrow{\rm w} = -5*16+ 2*40\\\\ \overrightarrow{\rm t} \cdot \overrightarrow{\rm w} = -80+ 80\\\\ \overrightarrow{\rm t} \cdot \overrightarrow{\rm w} = 0$