Once a scientist has examined all of the facts, performed experiments to test their question, and analyzed the results, then the
2 answers:
You might be interested in
The genealogy tree which is missing from the question is in the attachment.
Answer: 1) P1 = ; 2) P2 =
; 3)P3 =
Explanation: 1) According to the genealogy tree, the individual III-3 has a P1 = 1/2, because each of the parents are heterozygous for the condition, since one of the ofspring is affected.
2) For individual III-4, one of the parents is heterozygous for the condition, so the probability of being a carrier is P2 = 1/2.
3) Now, for individual IV-1 be affected, the parents has to be carrier. So, this probability, depends on the probability of each parent being heterozygous and that the individual will be carrying the condition, which means:
P3 = 1/2 · 1/2 · 1/4 = 1/16.
The probability of having the condition is 1/16 or 6.25%.
Answer:
0%
Explanation:
A bird with blue-tipped feathers (genotype Bb), when crossed with a white bird (genotype bb) can produce offspring with genotypes according to the following Punnett square:
In other to have entirely blue feathers, an offspring would have to have the BB genotype. Since it is not possible to obtain this genotype by crossing the birds in question, the percent chance that an offspring will have entirely blue feathers is 0%.