Distribute and simplify.
2(x+8)+6x
2x+16+6x
8x+16
8(x+2)
Answer: false false true true
Step-by-step explanation:
there is none
Answer:
They have a y-value of 0. They are in Quadrant 1. They are not above or below the origin.
Step-by-step explanation:
Answer:
3, 4, 7
Step-by-step explanation:
got it right on edg 2020
we know the triangle is an isosceles, so it has twin sides, and then the hypotenuse, since it's a right-triangle, we can just use the pythagorean theorem for that.
![\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{3\sqrt{2}}\\ b=\stackrel{opposite}{3\sqrt{2}}\\ \end{cases} \\\\\\ c=\sqrt{(3\sqrt{2})^2+(3\sqrt{2})^2}\implies c=\sqrt{(3^2\cdot 2)+(3^2\cdot 2)}\implies c=\sqrt{18+18} \\\\\\ c=\sqrt{36}\implies c=6](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20c%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3Dhypotenuse%5C%5C%20a%3D%5Cstackrel%7Badjacent%7D%7B3%5Csqrt%7B2%7D%7D%5C%5C%20b%3D%5Cstackrel%7Bopposite%7D%7B3%5Csqrt%7B2%7D%7D%5C%5C%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20c%3D%5Csqrt%7B%283%5Csqrt%7B2%7D%29%5E2%2B%283%5Csqrt%7B2%7D%29%5E2%7D%5Cimplies%20c%3D%5Csqrt%7B%283%5E2%5Ccdot%202%29%2B%283%5E2%5Ccdot%202%29%7D%5Cimplies%20c%3D%5Csqrt%7B18%2B18%7D%20%5C%5C%5C%5C%5C%5C%20c%3D%5Csqrt%7B36%7D%5Cimplies%20c%3D6)