Please help me my teacher already mad!!
2 answers:
Answer(s):
1. C. The graph has a slope of 0. (The slope is the change in the value of y over the change in the value of x--also known as rise over run--and there is no "slope" in this horizontal line. Think of slope like the steepness of a hill. If there is no steepness, then there is no slope.)
2. A. The graph decreases from left to right. (A negative slope is doing down a hill while positive is going up. So, if it's going down, then it's decreasing from left to right. Draw it out to better understand it if you're still confused.)
3. m = (Slope is rise over run. If the y is going down, it's a negative change. If up, then positive. For the x, if it's going to the right--or forwards, if your think about it, then it's positive and negative when going towards the negative left side. In this graph, the y decreases by one and the x increases by three. x/y would result in -1 over 3.)
4. m = (If there are no plotted points for you, just pick two points from the graph! Find the change in y and the change in x, put it in the format m = y/x and simplify if needed.)
5. m = (Like in no. 4, find the changes in y over x. Then, simplify if needed. For example, the rise over run of two points I found was 4/6, which is 2/3.)
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Answer:
Y = 3x^x is a graph that has exponential growth while y = 3^-x has exponential decay.
Y = 3x^x (-∞, 0) and (∞, ∞).
Y = 3x^-x (-∞, ∞) and (∞, 0).
Step-by-step explanation:
The infinity symbols were being used to represent the x and y values of each graph. I will call y = 3^x "graph 1" and y = 3^-x "graph 2".
When graph 1 had positive ∞ for its x value, its y value was reaching towards positive ∞. When its x was reaching for negative ∞, its y was going for 0.
For graph 2, however, when its x was reaching for positive ∞, its x was reaching for 0. When its x was reaching for negative ∞, its y was going for positive ∞.
Here's an image of the graphs:
