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Arturiano [62]
3 years ago
7

A bag contains rubber bands with lengths that are normally distributed with a mean of 6cm of length, and a standard deviation of

1.5cm. What percentage of the rubber bands can be expected to be shorter than 3cm?
Mathematics
1 answer:
Phoenix [80]3 years ago
6 0
There are 2cm is the answer is this what your looking for 
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Two cylinders are shown below which cylinder has a greater volume use 3.14 for pi
lesya [120]

Answer:

Cylinder Q has a greater volume

Step-by-step explanation:

For this question we need to utilise the volume of a cylinder which is

→ Volume of a cylinder = π × r² × h

Let's substitute in the values and then do the analysis

<u>Cylinder P</u>

→ Volume of a cylinder = π × r² × h

⇒ Substitute in the values

→ Volume of a cylinder = π × 4.25² × 14

⇒ Simplify

→ Volume of a cylinder = 794.430242277

<em>The volume of cylinder P is 794.430242277</em>

<em>-------------------------------------------------------------------------------------------------------</em>

<u>Cylinder Q</u>

→ Volume of a cylinder = π × r² × h

⇒ Substitute in the values

→ Volume of a cylinder = π × 7² × 8.5

⇒ Simplify

→ Volume of a cylinder = 1308.47334022

<em>The volume of cylinder Q is 1308.47334022</em>

<em>-------------------------------------------------------------------------------------------------------</em>

We can see that cylinder Q has a greater volume

8 0
3 years ago
Which piecewise function is shown in the graph?
mash [69]

Based on the characteristics of <em>linear</em> and <em>piecewise</em> functions, the <em>piecewise</em> function f(x) = \left \{ {{-0.5\cdot x +1, \,x < 0} \atop {2\cdot x - 2, \,x \ge 0}} \right. is shown in the graph attached herein. (Correct choice: A)

<h3>How to determine a piecewise function</h3>

In this question we have a graph formed by two different <em>linear</em> functions. <em>Linear</em> functions are polynomials with grade 1 and which are described by the following formula:

y = m · x + b     (1)

Where:

  • x - Independent variable.
  • y - Dependent variable.
  • m - Slope
  • b - Intercept

By direct observation and by applying (1) we have the following <em>piecewise</em> function:

f(x) = \left \{ {{-0.5\cdot x +1, \,x < 0} \atop {2\cdot x - 2, \,x \ge 0}} \right.

Based on the characteristics of <em>linear</em> and <em>piecewise</em> functions, the <em>piecewise</em> function f(x) = \left \{ {{-0.5\cdot x +1, \,x < 0} \atop {2\cdot x - 2, \,x \ge 0}} \right. is shown in the graph attached herein. (Correct choice: A)

To learn more on piecewise functions: brainly.com/question/12561612

#SPJ1

3 0
2 years ago
An economy pack of highlighters contains 12 yellow, 6 blue, 4 green, and 3 orange highlighters. An experiment consists of random
Serhud [2]

Answer:

The probability of choosing a blue or yellow highlighter when one yellow highlighter is picked is 17/25.

Step-by-step explanation:

Here, according to the question:

Total number of yellow highlighters  = 12

Total number of blue  highlighters  = 6

Total number of green highlighters  = 4

Total number of orange  highlighters  = 3

So, the total number of highlighters  =  12 + 6 + 4 + 3  = 25

Let E1 : Event of selecting a yellow highlighter.

P(E1)  = \frac{\textrm{Total number of yellow highlighters}}{\textrm{Total Highlighters}}  = \frac{12}{25}

Let E2 : Event of selecting blue or yellow highlighter ONCE yellow highlighter is selected.

So, the total yellow highlighters left after selecting one = 12 -1  = 11

Also, the number of blue highlighter  =  6

So, the TOTAL FAVORABLE options to E2 = 6+ 11 = 17

P(E2)  =

\frac{\textrm{Total number of yellow  + Blue   highlighters}}{\textrm{Total Highlighters}} = \frac{17}{25}

Hence, the probability that a blue or yellow highlighter is selected given that a yellow highlighter is selected is 17/25.

7 0
3 years ago
HELP PLEASE. 10 POINTS !!!!!!! ASAPPPP
Temka [501]
7x+4y=39 , 2x+4y=15
X-5 and y -1
3 0
3 years ago
What is the midpoint of the line segment with endpoints at (12,7)and (18,19)
Mrac [35]

Answer:

(15, 13)

Step-by-step explanation:

Midpoint is the half of the segment.

What I did to solve this was adding the two xs together to get 30 then find the average of 30 by dividing it by 2. This would give you 15

I did the same thing with the ys and got 13

hope this made sense

6 0
3 years ago
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