Dy/dx = (ycos(x))/(1 + y²)
(1 + y²)/y dy = cos(x) dx
(1/y + y) dy = cos(x) dx
Integrating:
ln(y) + y²/2 = sin(x) + c
ln(1) + 1/2 = sin(0) + c
c = 1/2
Thus,
ln(y) + y²/2 = sin(x) + 1/2
Answer:
(b) 36 degrees.
Step-by-step explanation:
K is the center of the circle so triangle KMN is isosceles and m < KMN = m KNM = 26 degrees ( base angles are equal)
So m < LMK = m <LMN - m < KMN
= 98 - 26
= 72 degrees.
Now triangle LKM is also isosceles since K is the center of the circle so
m < LKM = 180 - 2* 72
= 180 - 144
= 36 degrees.
Y=2 this is found with y=mx+b and the slope is 0 you cross at the y-axis on the 2
