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Ratling [72]
2 years ago
7

Which of the following is a trinomial?

Mathematics
1 answer:
sweet-ann [11.9K]2 years ago
5 0

Answer:

c

Step-by-step explanation:

because it has 3 parts. tri.

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Will give brainliest
klemol [59]

Your question is calling the figure ABCD, but the image is showing PQRS


Using the letters that you wrote:

Because the figure was only rotated and not scaled , the sides with the same letters would still be the same

So AB would be the same as A'B' ( Length of AB = Length of A′B)

and

BC = B'C'

CD = C'D'

AD = A'D'


Or by the picture:

PQ = P'Q'

QR = Q'R'

RS = R'S'

PS = P'S'





7 0
3 years ago
Read 2 more answers
It costs $36.00 to get into an amusement park. Treats, like cotton candy, caramel apples, and
spayn [35]

Answer:

d

Step-by-step explanation:

So the problem states,

52 = 36 + 4x

16 = 4x

x = 4 (must be less than or equal to)

3 0
2 years ago
What is the least common denominator for adding the fractions 4/15, 1/12, and 3/8
il63 [147K]
I think you want the least common multipule (exg LCM of 2,3,4 is 12)

so we find the factors and include all of them so like this

15=3 times 5
12=2 times 2 times 3
8=2 times 2 times 2

so to include all of them we include 3 2's, 1 3 and 1 5 or 2 times 2 times 2 times 3 times 5 or 8 times 15 or 4 times 30 or 120

the LCM is 120

so 4/15=32/120
1/12=10/120
3/8=45/120

add 32/120+10/120+45/120=(32+10+45)/120=87/120
5 0
3 years ago
Read 2 more answers
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3


has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
3 years ago
Read 2 more answers
For this spinner, what are the following probabilities? Answer in simplest fraction form using the form: x/y
luda_lava [24]
<h2>P(4) = 1/8</h2><h2>P(5) = 2/8 = 1/4</h2><h2>P(6) = 3/8</h2><h2>P(7) = 2/8 = 1/4</h2><h2>P(even number) = 4/8 = 1/2 </h2>
7 0
2 years ago
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