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Ratling [72]
2 years ago
7

Which of the following is a trinomial?

Mathematics
1 answer:
sweet-ann [11.9K]2 years ago
5 0

Answer:

c

Step-by-step explanation:

because it has 3 parts. tri.

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Somebody please help me!
Ierofanga [76]

Method:

First place the replace of p and r using brackets.

= 3(6) + 11.7(7)

3 times 6 is 18 and 11.7 times 7 is 81.9

= 18 + 81.9

add one and one together you get

= 99.9

<em>hope </em><em>it </em><em>helps</em>

6 0
3 years ago
point O lies between points M and P on a line. OM = 34z and OP = 36z -7. if point N is the midpoint of MP, what algebraic can yo
zalisa [80]
N=1/2MP? Since n would be the midpoint you have to divide the segment into two.
3 0
3 years ago
Please help answer these
BabaBlast [244]
You should use the ratio so 

2/ 4  = 6.5 / n  

n= 6.5 x 4  / 2 =  13 inches 


2- for two hours ------> four inches of snow 
for x hours -----> y inches of snow 
the equation is 
2/4 = x/ y 

x= 2y / 4 
 for x is the hours and y is the inches 

exercice 2
5 gr granula ----------------------> 1750 calories 
2 gr granula ----------------------> n ?? calories 

by cross multiplication 
n = 2 x1750 / 5 =  700 calories .

2-
she wants to eat 175 calories so 
u put granula under granula  and calories under calories to make this cross 

<span>5 gr granula ----------------------> 1750 calories 
</span>??? m granula ---------------------> 175 calories 
<span>by cross multiplication </span>
m = 175 x 5 / 1750 =  0.5 gr of granula 
8 0
3 years ago
The average American man consumes 9.8 grams of sodium each day. Suppose that the sodium consumption of American men is normally
Alex Ar [27]

Answer:

(a) The distribution of <em>X</em> is <em>N</em> (9.8, 0.8²).

(b) The probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c) The middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

Step-by-step explanation:

The random variable <em>X</em> is defined as the amount of sodium consumed.

The random variable <em>X</em> has an average value of, <em>μ</em> = 9.8 grams.

The standard deviation of <em>X</em> is, <em>σ</em> = 0.8 grams.

(a)

It is provided that the sodium consumption of American men is normally distributed.

The random variable <em>X</em> follows a normal distribution with parameters <em>μ</em> = 9.8 grams and <em>σ</em> = 0.8 grams.

Thus, the distribution of <em>X</em> is <em>N</em> (9.8, 0.8²).

(b)

If X ~ N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z ~ N (0, 1).

To compute the probability of  Normal distribution it is better to first convert the raw score (<em>X</em>) to <em>z</em>-scores.

Compute the probability that an American consumes between 8.8 and 9.9 grams of sodium per day as follows:

P(8.8

                           =P(-1.25

Thus, the probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c)

The probability representing the middle 30% of American men consuming sodium between two weights is:

P(x_{1}

Compute the value of <em>z</em> as follows:

P(-z

The value of <em>z</em> for P (Z < z) = 0.65 is 0.39.

Compute the value of <em>x</em>₁ and <em>x</em>₂ as follows:

-z=\frac{x_{1}-\mu}{\sigma}\\-0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8-(0.39\times 0.8)\\x_{1}=9.488\\x_{1}\approx9.5     z=\frac{x_{2}-\mu}{\sigma}\\0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8+(0.39\times 0.8)\\x_{1}=10.112\\x_{1}\approx10.1

Thus, the middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

4 0
3 years ago
Expand and simplify 3(x-2)+2(4x-1)
aliya0001 [1]
3(x-2)+2(4x-1)
=3x-6+8x-2
=11x-8
5 0
3 years ago
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