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kow [346]
2 years ago
14

The total cost for paperback books varies

Mathematics
1 answer:
postnew [5]2 years ago
4 0

Answer:

$113.81

Step-by-step explanation:

Find the cost for one book:

35.94 / 6 = 5.99

Multiply 5.99 with the number of books buying:

5.99 x 19 = 113.81

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Solve for x: 1 1/5 x -2 1/3 < 1/7 x+ 1 1/2
Firlakuza [10]
Solving inequalities is similar to solving a regular equation. The only thing you need to worry about with inequalities is that when you are dividing or multiplying by a negative number, you must flip the inequality sign. You won't have to worry about that here if the coefficient in front of x is positive when you divide!

Also remember:
- To add/subtract fractions, you have to turn all mixed numbers into improper fractions (if needed), <span>find a common denominator on both fractions (if needed), add/subtract the numerators, put the sum/difference over the common denominator, and simplify if needed. 

- To multiply fractions, multiply the numerators and multiply the denominators. Put the product of the numerators over the product of the denominators.

- To divide fractions, remember that dividing by a fraction is the same as multiplying by the inverse of that fraction (aka fraction flipped). 

- To turn mixed numbers into improper fractions, multiply the whole number by the denominator of the fraction. Add the numerator of the fraction to the product you get, and put that final sum over the original denominator.

Back to the problem:
</span>You are told that 1 \frac{1}{5} x - 2 \frac{1}{3} \ \textless \ \frac{1}{7} x + 1 \frac{1}{2} and you have to solve for x.
<span>
1) </span>Using the info for converting mixed numbers to improper fractions from above, you know that 1 \frac{1}{2} =  \frac{3}{2} and 2 \frac{1}{3} =  \frac{7}{3} and 1 \frac{1}{5} x =  \frac{6}{5} x. Now add/subtract using the info above, isolating the variable x by adding 2 \frac{1}{3} to both sides and subtracting \frac{1}{7} x from both sides. 
1 \frac{1}{5} x - 2 \frac{1}{3} \ \textless \ \frac{1}{7} x + 1 \frac{1}{2}\\&#10;\frac{6}{5} x -  \frac{7}{3} \ \textless \ \frac{1}{7} x + \frac{3}{2}\\&#10;(\frac{6}{5} x  - \frac{1}{7} x) \ \textless \ (\frac{3}{2} + \frac{7}{3})\\&#10;(\frac{42}{35} x  - \frac{5}{35} x) \ \textless \ (\frac{9}{6} + \frac{14}{6})\\&#10; \frac{37}{35} x \ \textless \   \frac{23}{6}

2) Divide both sides by \frac{37}{35} to get the inequality for x. Remember the info for dividing from above:
\frac{37}{35} x \ \textless \ \frac{23}{6}\\&#10;x \ \textless \  \frac{23}{6} \div \frac{37}{35}  \\&#10;x \ \textless \  \frac{23}{6} \times \frac{35}{37} \\&#10;x \ \textless \  \frac{805}{222}

Your final answer is x < \frac{805}{222} or x < 3 \frac{139}{222}.
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The answer is C.

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The angle turns through 1-9 of the circle
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Paula purchase 3 dvd and 7 cds and spent between 90 and 100. Each dvd costs the same amount the price of cd is 10 select all amo
sveticcg [70]

The options aren't given, however, the range of amount spent could be calculated

Answer:

Kindly check explanation

Step-by-step explanation:

Paula purchase 3 dvd and 7 cds and spent between 90 and 100. Each dvd costs the same amount the price of cd is 10 select all amounts that could be the price of the dvd

Given that :

DVD costs the same amount

Number of DVD's = 3

Cost of cds = 10

Number of cds = 7

Total cost of cd's = 10 * 7 = 70

Let the price of DVD = x

Total amount spent = 90 - 100

Lowest price of DVD :

(amount spent - price of cd) / number of dvd

(90 - 70) / 3 = 20 /3 = 6.667

Highest price :

(100 - 70) / 3 = 30 / 3 = 10

Hence the pice of each DVD will range between /

6.6666 and 10.

Hence, prices listed within the range above are possible.

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2 years ago
M–[(m–n)÷(−2)](−5), if m=−4, n=−6
Marrrta [24]

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