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aleksandrvk [35]

2 years ago

11

In quadrilateral ABCD what is m

1 answer:

sineoko [7]2 years ago

8 0

Answer:

B.99°

Step-by-step explanation:

105°+ 66°+90°+ angle c=360°

angle c= 360° - 261

=99°

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Mary Palm's checking account had a starting balance of $785.63. She wrote a check for $57.00 for groceries and a check for $125.

wariber [46]

785.63-(57+125)
=785.63-182
=603.63

603.63+57.25=$660.87

5 0

3 years ago

A company has 10 trucks. A truck has 15 pallets. A pallet has 7 boxes. A box has 50 containers. A container has 3 plastic bags.

Oliga [24]

Step-by-step explanation:

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6 0

1 year ago

Find the distance between the points (-2, 4) and (4, -6).<br> 0 212<br> 2/(10)<br> O2V(34)

Fittoniya [83]

Answer:

2 $\sqrt{34}$

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √(x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 2, 4) and (x₂, y₂ ) = (4, - 6)

d = $\sqrt{(4+2)^2+(-6-4)^2}$

= $\sqrt{6^2+(-10)^2}$

= $\sqrt{36+100}$

= $\sqrt{136}$ = $\sqrt{4(34)}$ = $\sqrt{4}$ × $\sqrt{34}$ = 2 $\sqrt{34}$

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7

Katen [24]

$\green{\large\underline{\sf{Solution-}}}$

<u>Given expression is </u>

$\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} }$

can be rewritten as

$\rm \: = \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\$

And

$\purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\$

So, using this identity, we

$\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} }$

can be further rewritten as

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)}$

$\rm \: = \: \dfrac{4}{25 - 1}$

$\rm \: = \: \dfrac{4}{24}$

$\rm \: = \: \dfrac{1}{6}$

<u>Hence, </u>

$\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}$

4 0

2 years ago

If r is seven more than the square of l, then r =

xenn [34]

I think its r=I+7 because that would be the equation

6 0

3 years ago