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3 years ago

Which of the following equations have exactly one solution?

Mathematics

1 answer:

Sonja [21]3 years ago

7 0

Answer:

Step-by-step explanation:

Because if you subtract 19x and 18 from each side it wont be 0=0, in other equatins there is infinity solutions

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Solomon can buy four sodas for $6 how much would 6 sodas cost

Bad White [126]

Answer:

6 soda's will cost $9.

Step-by-step explanation:

4 soda's costs $6.

Find the amount 2 soda's will cost. Divide 2 from both sides.

(4)/2 = 2

(6)/2 = 3

2 soda's will cost $3.

Now, solve for the cost for 6 soda's by multiply 3 to both sides.

2(3) = 6

3(3) = 9

6 soda's will cost $9.

7 0

3 years ago

Read 2 more answers

If x = -2, what does -x mean

pickupchik [31]

Answer:

Step-by-step explanation:

If,

x = -2

Then,

-x = -(-2)

=> -x = 2 (Ans)

6 0

3 years ago

When f(x) = –3, what is x? –29 –10 –3 –1

mariarad [96]

Answer:

x = - 1

Step-by-step explanation:

I hope this will help you

6 0

1 year ago

What is the total number of points scored by a player who makes 3 three-pointers, 5 two-pointers, and 6 free throws?

PolarNik [594]

25 because 3 threes is 9 and 5 twos is 10 so thats 19 plus 6 free throws which are 1 point so a total of 6

6 0

2 years ago

Read 2 more answers

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

8 0

2 years ago