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SOVA2 [1]
2 years ago
7

Find the Area of the Trapezoid below *

Mathematics
1 answer:
katrin2010 [14]2 years ago
5 0

Answer:

Hello! answer: C. 96 sq. cm

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I need help asap .....
NeX [460]
C is the correct answer
5 0
2 years ago
State the domain of 1b, then determine the equation of any vertical asymptotes and/or coordinates of any holes in the graph of t
Katena32 [7]

We have

f(x)=\frac{2x^2+x}{x^2-5x+6}

First we will factorize the function

f(x)=\frac{x(2x+1)}{\mleft(x-2\mright)(x-3)}

The domain is

\: \mleft(-\infty\: ,\: 2\mright)\cup\mleft(2,\: 3\mright)\cup\mleft(3,\: \infty\: \mright)

In this case, we have two vertical asymptotes

x-2=0

x=2

x-3=0

x=3

ANSWER

The domain is

\: \mleft(-\infty\: ,\: 2\mright)\cup\mleft(2,\: 3\mright)\cup\mleft(3,\: \infty\: \mright)

The vertical asymtotes

x-2=0

x=2

x-3=0

x=3

6 0
1 year ago
if an area can be washed at a rate of 4,900 cm2/ minute, how many square inches can be washed per hour?
Olenka [21]

Answer : 4.5 × 10⁴ square inches can be washed per hour.

Step-by-step explanation :

As we are given that an area can be washed at a rate of 4,900 cm²/min. Now we have to determine the square inches can be washed per hour.

Given conversions are:

1 cm = 0.39 in    and    1 hr = 60 min

As, 1 cm² = (0.39)² in²    and    1 min = 1/60 hr

So, 1cm^2/min=(0.39)^2\times 60in^2/hr

1cm^2/min=9.126in^2/hr

Now we have to determine the square inches can be washed per hour.

As, 1cm^2/min=9.126in^2/hr

So, 4900cm^2/min=\frac{4900cm^2/min}{1cm^2/min}\times 9.126in^2/hr=44717.4in^2/hr=4.5\times 10^4in^2/hr

Therefore, 4.5 × 10⁴ square inches can be washed per hour.

4 0
2 years ago
A line has a slope of -2 and the point (2,7) lies on the line. What is the y-intercept of the line?
Orlov [11]

Answer:

I really hope this helps

Step-by-step explanation:

brainliest please? :)

4 0
2 years ago
Help pls I really need this
Varvara68 [4.7K]

Answer:

{2 , 4} is the answer of this question.

7 0
3 years ago
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