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3 years ago

7

Find the Area of the Trapezoid below *

1 answer:

katrin2010 [14]3 years ago

5 0

Answer:

Hello! answer: C. 96 sq. cm

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Kinu has 7 memory sticks that contain data from his computer. Some of the me

ra1l [238]

Solving the system of equations, it is found that x = 3, that is, there are 3 128 MB memory sticks.

--------------------

We want to solve for x, thus, in the first equation, we write y as a function of x, that is:

$y = 7 - x$

Replacing in the second equation:

$128x + 512(7 - x) = 2432$

$128x + 3584 - 512x = 2432$

$384x = 1152$

$x = \frac{1152}{384}$

$x = 3$

x = 3, that is, there are 3 128 MB memory sticks.

A similar problem is given at brainly.com/question/24823220

6 0

2 years ago

4. Which of the following correctly orders the values below from least to greatest?

OLga [1]

0.75%, 3/4, 0.075. I think this correct.

5 0

3 years ago

Identify the basic shapes in the figure:)

IgorC [24]

Triangle and rectangle

6 0

3 years ago

Ana Sofia performed a transformation on APQR. She

stiv31 [10]

Answer:

a= 6 b=4

Step-by-step explanation:

-2+6=4

3+4+7

6 0

3 years ago

Complete the standard form of the equation of a hyperbola that has vertices at (-10, -15) and (70, -15) and one of its foci at (

Elena L [17]

Answer:

$\frac{(x-30)^{2}}{40^{2}} - \frac{(y+15)^{2}}{3^{2}} = 1$

Step-by-step explanation:

The equation of the horizontal hyperbola in standard form is:

$\frac{(x-k)^{2}}{a^{2}} - \frac{(y-k)^{2}}{b^{2}} = 1$

The position of its center is:

$C(x,y) = \left(\frac{-10 + 70}{2}, -15 \right)$

$C(x, y) = (30,-15)$

The values for c and a are respectively:

$a = 70 - 30$

$a = 40$

$c = 30 - (-11)$

$c = 41$

The remaining variable is computed from the following Pythagorean identity:

$c ^{2} = a^{2} + b^{2}$

$b = \sqrt{c^{2}-a^{2}}$

$b = \sqrt{41^{2}-40^{2}}$

$b = 3$

Now, the equation of the hyperbola is:

$\frac{(x-30)^{2}}{40^{2}} - \frac{(y+15)^{2}}{3^{2}} = 1$

3 0

3 years ago

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