Answer:
The fly will travel 20 miles before the runners collide with each other.
Explanation:
Since the runners are both traveling at the same speed, they will meet and collide in the exact middle of each other which is 5 miles away from their starting point. Since they are traveling at 5 mph, it will take exactly one hour before they collide. The fly is going 20 mph so it will travel 20 miles before the runners collide in one hour.
<span>In blues musicians also often refer to chord progressions using Roman numerals, as this facilitates transposing a song to a new key. For example, rock and blues musicians often think of the 12 bar blues as consisting of I, IV and V chords.
Thus a simple version of the 12 bar blues might be expressed as I/I/I/I IV/IV/I/I V/IV/I/I. By thinking of this blues progression in Roman numerals, a backup band or rhythm section could be instructed by a band leader to do the chord progression in any key.
For example if the band leader asked the band to play this chord progression in the key of C Major, the chords would be C/C/C/C F/F/C/C G/F/C/C.</span>
Bc it needs it to poop and pee and to even live n protect himself from
predators as seen above
Answer:
b ≈ 64 Kg/s
Explanation:
Given
Fd = −bv
m = 2.5 kg
y = 6.0 cm = 0.06 m
g = 9.81 m/s²
The object in the pan comes to rest in the minimum time without overshoot. this means that damping is critical (b² = 4*k*m).
m is given and we find k from the equilibrium extension of 6.0 cm (0.06 m):
∑Fy = 0 (↑)
k*y - W = 0 ⇒ k*y - m*g = 0 ⇒ k = m*g / y
⇒ k = (2.5 kg)*(9.81 m/s²) / (0.06 m)
⇒ k = 408.75 N/m
Hence, if
b² = 4*k*m ⇒ b = √(4*k*m) = 2*√(k*m)
⇒ b = 2*√(k*m) = 2*√(408.75 N/m*2.5 kg)
⇒ b = 63.9335 Kg/s ≈ 64 Kg/s
The compressional forces stemming from a convergent plate boundary.
There will also be earthquakes along the plate margin. This is also referred to as a collision boundary.
Hope this helps
