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Elina [12.6K]
3 years ago
14

The ball is pulled by a force called gravity. In what direction does gravity always pull the ball?​

Physics
2 answers:
Finger [1]3 years ago
6 0
What that guy up there said^^
vredina [299]3 years ago
4 0

Answer:

Gravity always pulls the ball toward the center of earth (the ground).

Explanation:

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How far will a rubber ball fall on 20 seconds?
Shtirlitz [24]

Given that:

time (t) = 20 s ,

        S = ?

We know that S = ut + 1/2 at²     meters

                       since free fall, a = g = 9.81 m/s² ; u =0 ;

                        S = 0 + 1/2 × 9.81 × 20²

                        <em> S= 1962 m</em>

7 0
4 years ago
A sled and its rider are moving at a speed of 4.0 m/s along a horizontal stretch of snow. The snow exerts a kinetic frictional f
ehidna [41]

Answer:

The acceleration of the sled is "0.49 m/s²". A further explanation is given below.

Explanation:

The given values are,

Speed,

V = 4.0 m/s

Coefficient of kinetic friction,

μ = 0.05

As we know,

⇒  F \mu=\mu mg

and,

⇒  a = \mu g

On substituting the given values, we get

⇒     =0.0 5\times 9.8

⇒     =0.49 \ m/s^2

5 0
3 years ago
‏Explain how an electron emitted by the photoelectric effect can have kinetic energy less than threshold energy ?
xenn [34]

Answer:

the photons (quanta of light) collide with the electrons, these electrons have to overcome the threshold energy that is the energy of union with the metal, and the energy that remains is converted to kinetic energy.

          K = E - Ф

Explanation:

The photoelectric effect is the emission of electrons from the surface of a metal.

This was correctly explained by Einstein, in his explanation the energy of the photons (quanta of light) collide with the electrons, these electrons have to overcome the threshold energy that is the energy of union with the metal, and the energy that remains is converted to kinetic energy.

          E = hf

          E = K + Ф

          K = E - Ф

The energy of the photons is given by the Planck relation E = hf and according to Einstein the number of joints must be added

            E = n hf

Therefore, depending on the value of this energy, the emitted electrons can have energy from zero onwards.

4 0
3 years ago
A 50-foot flagpole is at the entrance of a building that is 300 feet tall. If the length of the flagpole's shadow is 30 feet at
natka813 [3]
First you will want to sketch out both of the situations. It should be two sketches, one for the flagpole and one for the building.

To solve this, you will want to create a proportion.

Flagpole height/flagpole shadow=building height/building shadow

Therefore, it should look like this:
50/30= 300/x

Solve for x:
50x=9,000
X= 180 feet

YOUR ANSWER IS C.
7 0
3 years ago
A cannonball has just been shot out of a cannon aimed 45∘ above the horizontal rightward direction. Drag forces cannot be neglec
Novosadov [1.4K]

Answer:

The free-body diagram of the cannonball is found in the attachment below

<em>Note The question is incomplete. The complete question is as follows:</em>

<em>A cannonball has just been shot out of a cannon aimed 45∘ above the horizontal rightward direction. Drag forces cannot be neglected.</em>

<em>Draw the free-body diagram of the cannonball.</em>

Explanation:

Free-body diagrams are diagrams used to show the relative magnitude and direction of all forces acting upon an object in a given situation.

In order to construct free-body diagrams, it is important to know the various types of forces acting on the object in that situation. Then, the direction in which each of the forces is acting is determined. Finally the given object is drawn using any given representation, usually a box, and the direction of action of the forces are represented using arrows.

In the given situation of a cannonball which has just been shot out of a cannon aimed 45∘ above the horizontal rightward direction., the forces acting on it are:

F = force exerted by the cannon acting in the direction of angle of projection

Fdrag = drag force. The drag force acts in a direction opposite to the force exerted by the cannon

Fw = weight of the cannonball acting in a downward direction

The free body diagram is as shown in the attachment below.

6 0
3 years ago
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