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2 years ago

Find the volume of a rectangular prism that is 8m long, 4m wide, and 300cm high

Physics

2 answers:

ch4aika [34]2 years ago

7 0

Answer:

Formular:

${ \boxed{ \bf{v = length \times width \times height}}}$

» length, l = 8m

» width, w = 4m

» height, h = 300cm = 3 m

${ \tt{• Therefore :→}} \: { \sf{ volume = (8 \times 4 \times 3)}} \\ → { \sf{ \underline{ \: \: volume = 96 \: {m}^{3} \: \: }}}$

konstantin123 [22]2 years ago

6 0

L=8m
B=4m
H=300cm=3m

$\\ \bull\tt\longmapsto Volume=LBH$

$\\ \bull\tt\longmapsto Volume=8(4)(3)$

$\\ \bull\tt\longmapsto Volume=96m^3$

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During the motion of the slinky in a transverse wave, what do the particles of the slinky coil do?

Mazyrski [523]

Answer:

C.) The slinky particles move up and down

Explanation:

Transverse Wave-

A wave that has a disturbance perpendicular to the wave motion

Hello! This is the correct answer! Have a blessed day! :)

If you are in K12, please review the lesson! :) It will give you some very helpful definitions! I hope this helped!

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2 years ago

When you approach a yield sign, while trying to enter or merge onto another road, traffic already on that road has the right of

kogti [31]

TRUE. When you approach a yield sign, while trying to enter or merge onto another road, traffic already on that road has the right of way.

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3 years ago

Read 2 more answers

Covert 35000000 miles to meters and show how you got the answer?

Lina20 [59]

Answer:

56327040000 metres

Explanation:

1 mile =

1609.344 metres

35000000 miles = x meters

we represent x by the number of meters which the requested miles maps to

we cross multiply, so 1609.344×35000000 = 1 × x

x =56327040000 metres

8 0

3 years ago

A bullet glider and a target glider both have a mass of 0.200 kg. The bullet glider is moving 0.450 m/s

Romashka [77]

Answer:

the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Explanation:

When the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Changes can occur that the gliders unite and move with a cosecant speed less than the initial one.

The whole process must be analyzed using conservation of the moment.

p₀ = m v₀

celestines que clash case

p_f = (m + M) v

po = pf

m v₀ = (n + M) v

v = $\frac{m}{m+M}$

calculemos

v= $\frac{0.200}{0.200+M} 0.450$

v= 0.09 m/s

elastic shock case

p₀ = m v₀

p_f = m v₁ +M v₂

p₀ = p_f

m v₀ = m v₁ + m v₂

6 0

3 years ago

Q1: A runner is jogging in a straight line at a steady vr= 6.8 km/hr. When the runner is L= 2.4 km from the finish line, a bird

serious [3.7K]

Answer:

Q1: 3.2km

Q2: 4.8K

Explanation:

Q1:

So db is the distance of bird, and dr is the distance of runner

db = 2vr and the distance of bird is going to be 2 times greater than the runner.

formulas: db = 2vr & db = 2dr

db = 2dr
L + (L - x) = 2x
2L - x = 2x
2L = 3x
x = $\frac{2}{3}$ L

Insert it in x = $\frac{2}{3}$ L

$\frac{2}{3}$ (2.4km) = 1.6km

Now we use formula db = 2dr

db = 2L - x
db = 2(2.4km) - 1.6km
db = 3.2km

Q2:

Formulas: Vr = L /Δt & Vb = db/Δt

Vr = L/ Δt ⇒ Δt = $\frac{L}{Vr}$
$\frac{2.4km}{6.8km/hr}$
$\frac{6}{17}hr$

(Km cancel each other)

Vb = db/Δt ⇒ db = VbΔt
13.6km/hr $(\frac{6}{17}hr )$
4.8km

(hr cancel each other)

Hope it helps you :)

6 0

3 years ago