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never [62]
3 years ago
9

Which statement is not true about General Edward Braddock?A.He captured Fort Duquesne.B.He was killed in battle.C.He did not res

pect colonial soldiers.D.He ignored early early warnings
Mathematics
1 answer:
sergeinik [125]3 years ago
3 0

Answer:

A. He captured Fort Duquesne.

Step-by-step explanation:

General Edward Braddock was fatally injured in the battle field and died of wounds. He insisted upon using open field tactics which turned out to be very fatal leading to the death of 1000 soldiers. He did ignore the early warnings of his aides regarding his strategy.

A British force led by General Edward Braddock, moving to take Fort Duquesne, was defeated by a force of French and Canadian troops under Captain Daniel Liénard de Beaujeu with its American Indian allies.

Consequently, he failed to capture Fort Duquesne. So statement A is not true.

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</span>
Year:        1984     1989     1993     1997     2001     2003

Percent:    7.8       16.3       26.2      38.9     49.2      62.1

The scatter plot of the data is attached with the x-axis representing the number of years after 1980 and the y-axis representing the percent increase <span>of donations made on behalf of a non-profit organization.

To find the equation for the line of regression where </span><span>the x-axis representing the number of years after 1980 and the y-axis representing the percent increase of donations made on behalf of a non-profit organization.
\begin{center}&#10;\begin{tabular}{ c| c| c| c| }&#10; x & y & x^2 & xy \\ [1ex] &#10; 4 & 7.8 & 16 & 31.2 \\  &#10; 9 & 16.3 & 81 & 146.7 \\ &#10;13 & 26.2 & 169 & 340.6 \\ &#10;17 & 38.9 & 289 & 661.3 \\ &#10;21 & 49.2 & 441 & 1,033.2 \\ &#10;23 & 62.1 & 529 & 1,428.3 \\ [1ex]&#10;\Sigma x=87 & \Sigma y=200.5 & \Sigma x^2=1,525 & \Sigma xy=3,641.3  &#10;\end{tabular}&#10;\end{center}
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Recall that the equation of the regression line is given by
y=a+bx
where
a= \frac{(\Sigma y)(\Sigma x^2)-(\Sigma x)(\Sigma xy)}{n(\Sigma x^2)-(\Sigma x)^2} = \frac{200.5(1,525)-87(3,641.3)}{6(1,525)-(87)^2}  \\  \\ = \frac{305,762.5-316793.1}{9,150-7,569} = \frac{-11,030.6}{1,581} =-6.977
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b= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{n(\Sigma x^2)-(\Sigma x)^2} = \frac{6(3,641.3)-(87)(200.5)}{6(1,525)-(87)^2}  \\  \\ = \frac{21,847.8-17,443.5}{9,150-7,569} = \frac{4,404.3}{1,581} =2.7858

Thus, the equation of the regresson line is given by
y=-6.977+2.7858x

The graph of the regression line is attached.

Using the equation, we can predict the percent donated in the year 2015. Recall that 2015 is 35 years after 1980. Thus x = 35.

The percent donated in the year 2015 is given by
-6.977+2.7858(35)=-6.977+97.503=90.526

Therefore, the percent donated in the year 2015 is predicted to be 90.5

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