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Dmitry [639]
2 years ago
12

A bag contains 12 red checkers and 12 black checkers. 1/randomly drawing a red checker 2/randomly drawing a red or black checker

Mathematics
1 answer:
8_murik_8 [283]2 years ago
7 0

Answer:

(I suppose that we want to find the probability of first randomly drawing a red checker and after that randomly drawing a black checker)

We know that we have:

12 red checkers

12 black checkers.

A total of 24 checkers.

All of them are in a bag, and all of them have the same probability of being drawn.

Then the probability of randomly drawing a red checkers is equal to the quotient between the number of red checkers (12) and the total number of checkers (24)

p = 12/24 = 1/2

And the probability of now drawing a black checkers is calculated in the same way, as the quotient between the number of black checkers (12) and the total number of checkers (23 this time, because we have already drawn one)

q = 12/23

The joint probability is equal to the product between the two individual probabilities:

P = p*q = (1/2)*(12/23) = 0.261

T

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Step-by-step explanation:

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3 years ago
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How to find 62%of $400​
gayaneshka [121]

Answer:

248

Step-by-step explanation:

Solution for What is 400 percent of 62:

400 percent *62 =

(400:100)*62 =

(400*62):100 =

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Now we have: 400 percent of 62 = 248

Question: What is 400 percent of 62?

Percentage solution with steps:

Step 1: Our output value is 62.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$62=100\%.

Step 4: Similarly, x=400\%.

Step 5: This results in a pair of simple equations:

62=100\%(1).

x=400\%(2).

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

\frac{62}{x}=\frac{100\%}{400\%}

Step 7: Again, the reciprocal of both sides gives

\frac{x}{62}=\frac{400}{100}

\Rightarrow x=248

Therefore, 400 of 62 is 248

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3 years ago
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1:2

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5 0
3 years ago
2
GaryK [48]

Answer:

B_2=4\pi r^2

see the explanation

Step-by-step explanation:

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B=\pi r^{2}

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The new area of the base is 4 times the area of the original base

7 0
3 years ago
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