Question

A bag contains 12 red checkers and 12 black checkers. 1/randomly drawing a red checker 2/randomly drawing a red or black checker

Answer 1

Answer:

(I suppose that we want to find the probability of first randomly drawing a red checker and after that randomly drawing a black checker)

We know that we have:

12 red checkers

12 black checkers.

A total of 24 checkers.

All of them are in a bag, and all of them have the same probability of being drawn.

Then the probability of randomly drawing a red checkers is equal to the quotient between the number of red checkers (12) and the total number of checkers (24)

p = 12/24 = 1/2

And the probability of now drawing a black checkers is calculated in the same way, as the quotient between the number of black checkers (12) and the total number of checkers (23 this time, because we have already drawn one)

q = 12/23

The joint probability is equal to the product between the two individual probabilities:

P = p*q = (1/2)*(12/23) = 0.261

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