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egoroff_w [7]
3 years ago
6

Zane bought 2 packages of candy bars. He had fewer than 22 candy bars. Write an inequality to find b, the number of candy bars i

n each
package.
Mathematics
1 answer:
Alex73 [517]3 years ago
4 0
2x < 22 to solve

x < 11 because 2x/2 < 22/2 = x< 11
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Scrat [10]

Answer:

b

Step-by-step explanation:


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3 years ago
Matt and Kelly both purchased the same type mulch to be used in a garden. They both spent exactly $60 each on mulch. • Matt purc
hichkok12 [17]

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<em>B.) Kelly got the better deal.</em>

Step-by-step explanation:

7 0
3 years ago
PLEASE HELP!!!
Morgarella [4.7K]

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4 0
3 years ago
Solve the equation: k^2+5k+13=0
mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}  \\

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a = 1 , b = 5 , c = 13

So we have

k =  \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)}  \\  =  \frac{ - 5 \pm \sqrt{25 - 52} }{2}  \\  =  \frac{ - 5 \pm \sqrt{ - 27} }{2}  \:  \:  \:  \:  \:  \:  \\  =  \frac{ - 5  \pm3 \sqrt{3}  \: i}{2}  \:  \:  \:  \:  \:  \:

<u>Separate the solutions</u>

k_1 =  \frac{ - 5 + 3 \sqrt{3} \: i }{2}  \:  \:  \:  \: or \\ k_2 =  \frac{ - 5 - 3 \sqrt{3}  \: i}{2}

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

k_1 =  -  \frac{5}{2}  +  \frac{3 \sqrt{3} }{2}  \: i \:  \:  \:  \: or \\ k_2 =  -  \frac{5}{2}  -  \frac{3 \sqrt{3} }{2}  \: i

Hope this helps you

8 0
2 years ago
What is the slope of the line that contains the points (9,-4) and (1,-5)?
Lyrx [107]

Answer:

Step-by-step explanation:

hello .....

note : the slope of the line (AB) is :

m = (YB -YA)/(XB - XA)

given  :  A(9,-4) and B (1,-5)

m= ((-5)-(-4))/(1-9)

m= 1/8

8 0
2 years ago
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