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3 years ago

Find the cost of 4.8 kilograms of potatoes at the price of $0.75 a kilogram?

Mathematics

1 answer:

Gelneren [198K]3 years ago

3 0

Answer: $3.60

Step-by-step explanation:

If you need 4.8 kilograms of potatoes and each kilograms costs $0.75, then we should multiply 0.75 by 4.8 to find the cost of 4.8 kilograms of potatoes.

4.8 x 0.75 = 3.6.

Therefore, the cost of 4.8 kilograms is $3.60 dollars. I hope this helps, and good luck!

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Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

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Differentiate the equation with respect to time t, such that

$\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)$

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To differentiate the product,

Let r² = u, so that

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)$

Then, using product rule

$\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]$

Since $u = r^{2}$

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Using the Chain's rule

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Then,

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

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From the question

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$180 = \frac{1}{3}\pi (99)^{2}h$

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$236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]$

$236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]$

$708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}$

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