Answer:
INF for first while D for second
Step-by-step explanation:
Ok I think I read that integral with lower limit 1 and upper limit infinity
where the integrand is ln(x)*x^2
integrate(ln(x)*x^2)
=x^3/3 *ln(x)- integrate(x^3/3 *1/x)
Let's simplify
=x^3/3 *ln(x)-integrate(x^2/3)
=x^3/3*ln(x)-1/3*x^3/3
=x^3/3* ln(x)-x^3/9+C
Now apply the limits of integration where z goes to infinity
[z^3/3*ln(z)-z^3/9]-[1^3/3*ln(1)-1^3/9]
[z^3/3*ln(z)-z^3/9]- (1/9)
focuse on the part involving z... for now
z^3/9[ 3ln(z)-1]
Both parts are getting positive large for positive large values of z
So the integral diverges to infinity (INF)
By the integral test... the sum also diverges (D)
What are you trying to say?
<h3>
Answer is choice D) 5:3</h3>
Explanation:
The volumes are in the ratio 3625:783 which reduces fully to 125:27 after dividing both parts by the GCF 29.
Both 125 and 27 are perfect cubes because 125 = 5^3 and 27 = 3^3
Therefore, the volume ratio 125:27 turns to the linear scale factor ratio 5:3
If you were to cube both sides of the linear ratio 5:3, you would get the volume ratio 125:27. Cube rooting both sides will have you go in reverse.
