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ExtremeBDS [4]
3 years ago
6

NO LINKS OR WILL BE REPORTED

Mathematics
1 answer:
V125BC [204]3 years ago
8 0
The answer is D. Call number of tickets is ‘x’ and amount $ collected is ‘y’. If x=5, y=3x5=15.
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If f (1) =4 and f(4)= f (n-1)-4 then find the value of f(4)
GaryK [48]

f(1) = 4 is given

f(n) = f(n-1)-4 is the recursive step or rule

f(2) = f(2-1)-4 ... replace n with 2

f(2) = f(1) - 4

f(2) = 4-4 ... replace f(1) with 4

f(2) = 0

----------

Repeat for n = 3

f(n) = f(n-1)-4

f(3) = f(3-1)-4

f(3) = f(2) - 4

f(3) = 0 - 4 .... replace f(2) with 0, which is from f(2) = 0 found earlier

f(3) = -4

---------

Repeat for n = 4

f(n) = f(n-1)-4

f(4) = f(4-1)-4

f(4) = f(3) - 4

f(4) = -4-4 ... plug in f(3) = -4

f(4) = -8

<h3>Answer is   -8</h3>
3 0
3 years ago
Haddie wrote a check to the grocery store for $156.00. However, when she looks at her check register later that night, she sees
evablogger [386]
Haddie wrote a check to the grocery store for $156.00. And turns out to only become 122.66 dollars the time she checked it later that night.Now, when she checked it in her banks, I believe there are fees charged to her written check. Now, let's find out how much will that be:=> 156 dollarss to 122.66 dollars=> 33.34 dollars=> 33.34 / 156 =0.21=> 0.21 * 100% = 21%<span>Thus, the bank opted 21% of her written check</span>
5 0
3 years ago
Simplify the complex numbers using de Moivre's Theorem and match them with their solutions.
alexandr1967 [171]

For the numbers in a+bi form, convert to polar form:


1+i=\sqrt2\dfrac{1+i}{\sqrt2}=\sqrt2\left(\cos\dfrac\pi4+i\sin\dfrac\pi4\right)

By DeMoivre's theorem,

(1+i)^5=(\sqrt2)^5\left(\cos\dfrac{5\pi}4+i\sin\dfrac{5\pi}4\right)=4\sqrt2\dfrac{-1-i}{\sqrt2}=-4-4i


-1+i=\sqrt2\dfrac{-1+i}{\sqrt2}=\sqrt2\left(\cos\dfrac{3\pi}4+i\sin\dfrac{3\pi}4}\right)

\implies(-1+i)^6=(\sqrt2)^6\left(\cos\dfrac{18\pi}4+i\sin\dfrac{18\pi}4\right)=8i


\sqrt3+i=2\dfrac{\sqrt3+i}2=2\left(\cos\dfrac\pi6+i\sin\dfrac\pi6\right)

\implies2(\sqrt3+i)^{10}=2^{11}\left(\cos\dfrac{10\pi}6+i\sin\dfrac{10\pi}6\right)=2^{11}\dfrac{1-i\sqrt3}2=2^{10}(1-i\sqrt3)


For the numbers already in polar form, DeMoivre's theorem can be applied directly:


2\left(\cos20^\circ+i\sin20^\circ\right)^3=2\left(\cos60^\circ+i\sin60^\circ\right)=2\dfrac{1+i\sqrt3}2=1+i\sqrt3


2\left(\cos\dfrac\pi4+i\sin\dfrac\pi4\right)^4=2(\cos\pi+i\sin\pi)=-2


At second glance, I think the 2s in the last two numbers should also be getting raised to the 3rd and 4th powers:


\left(2(\cos20^\circ+i\sin20^\circ)\right)^3=8\left(\cos60^\circ+i\sin60^\circ\right)=4+4\sqrt3

\left(2\left(\cos\dfrac\pi4+i\sin\dfrac\pi4\right)\right)^4=16(\cos\pi+i\sin\pi)=-16

4 0
3 years ago
This is a question about factoring trinomials<br><br> x^2+7x+10
soldier1979 [14.2K]

Answer:

(x+2)(x+5) here if im wrong my bad bro

Step-by-step explanation:

dont u just hate these bots just taking the points ._.

7 0
3 years ago
In one version of trail mix, there are 3 cups of peanuts mixed with 2 cups of raisins. In another version of trail mix, there ar
vagabundo [1.1K]

Answer:

No

Step-by-step explanation:

The 4.5 cups of peanuts should be 4

3 0
3 years ago
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