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ahrayia [7]
2 years ago
12

2. How many solutions does the equation x(x + 12) = 0 have?

Mathematics
1 answer:
xeze [42]2 years ago
5 0

Answer:

Tanong mo sa teacher mo ha ha ha ha

You might be interested in
What part of 28 is 17?
timurjin [86]

Answer:

4

Step-by-step explanation:

Divide 28 by 4 to get 7

7 0
2 years ago
5
Dimas [21]

Answer:

0.150 < (Proportion of Sandy's pie) < 0.167

15% < (Percentage of Sandy's pie) < 16.7%

Step-by-step explanation:

Total percentage of pie = 100% or 1

George, Sandy, Carlos, and Michelle all ate a piece of the pie.

George ate a fraction of 0.150

Michelle ate a fraction of (1/6) = 0.167

Carlos ate a fraction of (1/7) = 0.143

The amount of pie left = 1 - 0.15 - (1/6) - (1/7) = 0.5405

And Sandy is known to eat more than two of her friends, but less than one of them.

Of the amount of pie eaten by the first 3 friends, (1/6) is the highest proportion.

Hence, it is evident that Sandy ate more than 0.143 and 0.150 (Carlos and George) but less than Michelle (0.167).

So, mathematically, the possible proportion of cake that Sandy ate is

0.150 < (Proportion of Sandy's pie) < 0.167

Hope this Helps!!!

7 0
2 years ago
Plot each complex number and find its absolute value. 2 - 2i
sammy [17]

Answer:

(2,-2) and i think the absolute value might jus be i

8 0
3 years ago
Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are
Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

.

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}.

Recall that \binom{n}{k}= \frac{n!}{k!(n-k)!} In this case, the student passes if X is at least four correct questions, then

P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696

c)The expected value of a binomial random variable with parameters n and p is E[X] = np. IN our case, n=6 and p =0.2. Then the expected value of correct answers is 6\cdot 0.2 = 1.2

5 0
3 years ago
At the beginning of an experiment, the number of bacteria in a colony was counted at time t=O. The number of bacteria in the col
yan [13]

Answer:

1092

Step-by-step explanation:

We have been given that the number of bacteria in the colony t minutes after the initial count modeled by the function B(t)=9(3)^t. We are asked to find the average rate of change in the number of bacteria over the first 6 minutes of the experiment.

We will use average rate of change formula to solve our given problem.

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

Upon substituting our given values, we will get:

\text{Average rate of change}=\frac{b(6)-b(0)}{6-0}

\text{Average rate of change}=\frac{9(3)^6-9(3)^0}{6}

\text{Average rate of change}=\frac{9(729)-9(1)}{6}

\text{Average rate of change}=\frac{6561-9}{6}

\text{Average rate of change}=\frac{6552}{6}

\text{Average rate of change}=1092

Therefore, the average rate of change in the number of bacteria is 1092 bacteria per minute.

8 0
2 years ago
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