Answer:
See explanation
Step-by-step explanation:
Given the inequality 
A) Add -3 to both sides of inequality:
Divide by -7 (remember, dividing the inequality by negative number changes the sign of inequality):
B) Plot open circle at -6 on the number line and shade all values of x which go to the left from -6 (see attached diagram).
Answer:
Since it does not plug in to the second linear equation, the ordered pair is not a solution of the linear system.
Step-by-step explanation:
(-1,3); y = -7x -4 y = 8x + 5 3 =7 - 4 3 =/ - 8 + 5
Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
50
64=1, 2, 4, 8, 16, 32, 64
80
