Question

0.125 C of charge flow out of a

Answer 1

$\huge \mathrm{\longmapsto \: Answer}$

• Charge (q) = 0.125 C

• Time (t) = 6.30 sec

• Potential difference (v) = 5.00 V

• electric current (i) = ?

• resistance (r) = ?

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We know,

$\boxed{\mathrm{current = \dfrac{charge}{time}} }$

• $i = \dfrac{0.125}{6.30}$

• $i = \dfrac{125}{6300}$

Now,

$\boxed{ \mathrm{potential \: \: difference = i\times r}}$

• $5 = \dfrac{125}{6300} \times r$

• $r = \dfrac{5 \times 6300}{125}$

• $r = \dfrac{6300}{25}$

• $\boxed{ \mathrm {r = 252 \: \: ohms}}$

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$\mathrm{ \#TeeNForeveR}$