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3 years ago

12

In the xy-plane, a line segment is dilated by a scale factor of 2. The dilation is centered at a

1 answer:

Ber [7]3 years ago

8 0

Answer: Choice one is Parallel

Choice two is half

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What to write it here

Orlov [11]

Answer:

84 degrees

Step-by-step explanation:

Angle A = 83 degrees

Angle B = x degrees

Angle C = 135 degrees

Angle CDE = 122 degrees

We know that the four inner corners of a quadrilateral should add up to 360 degrees. Two supplementary angles will add up to 180 degrees. Adjacent angles on a straight line will always be supplementary. Knowing this, just solve for <ADC and add that amount to <A and <C. Then, subtract that sum from 360 degrees.

<ADC = 180-122 = 58

58+83+135 = 276

360-276 = 84 degrees

7 0

2 years ago

G(x) = -0.5x^2 + 4x – 2

-BARSIC- [3]

Answer:

Step-by-step explanation:

What is the question?

g(x) = -0.5x² + 4x - 2 is a down-opening parabola. Do you need to know how to put it in vertex form?

vertex (4,6)

focus (4,5.5)

5 0

2 years ago

What is the probability that a randomly number from 20 to 30 is divisible by 3 and then divisible by 12 after replacing first

tester [92]

Probability of divisibility by3=4/11
probability of divisibility by 12 =1/11
probability of divisibility by 12 and 3=4/11×1/11
answer is 4/121

7 0

3 years ago

The fourth graders are going to the

natta225 [31]

Answer: 15

Step-by-step explanation: there is a total of 126 people just find the first number that's divisible by 9 that's above it and divide

7 0

3 years ago

pH measurements of a chemical solutions have mean 6.8 with standard deviation 0.02. Assuming all pH measurements of this solutio

aalyn [17]

Answer: 2.14 %

Step-by-step explanation:

Given : pH measurements of a chemical solutions have

Mean : $\mu=6.8$

Standard deviation : $\sigma=0.02$

Let X be the pH reading of a randomly selected customer chemical solution.

We assume pH measurements of this solution have a nearly symmetric/bell-curve distribution (i.e. normal distribution).

The z-score for the normal distribution is given by :-

$z=\dfrac{x-\mu}{\sigma}$

For x = 6.74

$z=\dfrac{6.74-6.8}{0.02}=-3$

For x = 6.76

$z=\dfrac{6.76-6.8}{0.02}=-2$

The p-value = $P(6.74$

$P(z$

In percent, $0.0214\times=2.14\%$

Hence, the percent of pH measurements reading below 6.74 OR above 6.76 = 2.14%

6 0

3 years ago