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Sveta_85 [38]
3 years ago
14

Please help 8x -4 - 6x + 9 ​

Mathematics
1 answer:
andre [41]3 years ago
8 0
Your answer should be 2x+5 if you are supposed to simply the expression
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1/3 times 3.14 times 16 times 6 rounded two decimal places
Sergeeva-Olga [200]
The answer is 100.48

(If you are actually multiplying by pi rather than 3.14, then the answer is 100.53)
5 0
3 years ago
Of the CP of 15 articles equals to the SP of 12 articles, find the gain percent.<br>an<br>ple 4:​
Rasek [7]

<u><em>Question</em></u>

<em>If the CP of 15 articles equals to the SP of 12 articles, find the gain percent.</em>

<em></em>

Answer:

gain percent = 25%

Step-by-step explanation:

To solve the question given, we will follow the steps below:

gain%  =   \frac{s.p - c.p}{c.p}  ×    100%

But from the question;

"CP of 15 articles equals to the SP of 12 articles", this implies that

15 c.p  =  12 s.p

s.p = 15c.p  /   12

s.p  = \frac{15 c.p}{12}       =   \frac{5c.p}{4}

s.p  =  \frac{5c.p}{4}

substitute  s.p  =  \frac{5c.p}{4}   into the formula

gain%  =   \frac{s.p - c.p}{c.p}  ×    100%

      =\frac{\frac{5c.p}{4} -  c.p }{c.p}     ×    100%

       =  \frac{\frac{5c.p - 4c.p}{4} }{c.p}      ×    100%

  =   \frac{c.p}{4}   ÷   c.p      ×    100%

= \frac{c.p}{4}     ×   \frac{1}{c.p}    ×    100%

=   \frac{1}{4}  ×    100%

=  25 %

3 0
3 years ago
Using 4 equal-width intervals, show that the trapezoidal rule is the average of the upper and lower sum estimates for the integr
prisoha [69]

Split up the interval [0, 2] into 4 subintervals, so that

[0,2]=\left[0,\dfrac12\right]\cup\left[\dfrac12,1\right]\cup\left[1,\dfrac32\right]\cup\left[\dfrac32,2\right]

Each subinterval has width \dfrac{2-0}4=\dfrac12. The area of the trapezoid constructed on each subinterval is \dfrac{f(x_i)+f(x_{i+1})}4, i.e. the average of the values of x^2 at both endpoints of the subinterval times 1/2 over each subinterval [x_i,x_{i+1}].

So,

\displaystyle\int_0^2x^2\,\mathrm dx\approx\dfrac{0^2+\left(\frac12\right)^2}4+\dfrac{\left(\frac12\right)^2+1^2}4+\dfrac{1^2+\left(\frac32\right)^2}4+\dfrac{\left(\frac32\right)^2+2^2}4

=\displaystyle\sum_{i=1}^4\frac{\left(\frac{i-1}2\right)^2+\left(\frac i2\right)^2}4=\frac{11}4

4 0
3 years ago
The sum of three consecutive number is 633 ,find the numbers
chubhunter [2.5K]

Answer:

210, 211, 212

Step-by-step explanation:

If we denote the first number as x, then the second number can be written as x + 1 and the third number as x + 2.

The equation is:

x + (x + 1) + (x + 2) = 633

3x + 3 = 633

3x = 633 - 3

3x = 630

x = 210

So the three consecutive numbers we're looking for are: 210, 211, 212

8 0
2 years ago
(Please help quick! will do brainliest!!)
Kaylis [27]

Answer:

110

Step-by-step explanation:

that's what I got, I apologize if it's incorrect

4 0
2 years ago
Read 2 more answers
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