Which point is on the graph of f(x)=|x-6|+7?
(5,8)
(8,10)
(6,9)
(3,11)
(4,12)
2 answers:
Answer:
(5, 8)
Step-by-step explanation:
Convert the f(x) = to a y =
f(x) = | x - 6 | + 7
y = | x - 6 | + 7
Plug in the values and prove
y = | x - 6 | + 7
(5,8)
8 = | 5 - 6 | + 7
8 = | -1 | + 7
8 = 1 + 7
8 = 8; true
(8,10)
10 = | 8 - 6 | + 7
10 = | 2 | + 7
10 = 2 + 7
10 = 9; false
(6, 9)
9 = | 6 - 6 | + 7
9 = | 0 | + 7
9 = 0 + 7
9 = 7; false
(3, 11)
11 = | 3 - 6 | + 7
11 = | -3 | + 7
11 = 3 + 7
11 = 10; false
(4, 12)
12 = | 4 - 6 | + 7
12 = | -2 | + 7
12 = 2 + 7
12 = 9; false
Therefore the only one which falls on the graph is (5, 8)
Hope this helps :)
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Hope this helped:)
Nimber line with an open crpircle on 3,shading to the right and an open circle on 5 ,shading to the left
