let the numbers be x and y
x + y = 1600 ----*
12%x = 20%y
0.12x = 0.2y
y = <u>0</u><u>.</u><u>1</u><u>2</u><u>x</u>
0.2
y = 0.6x
substitute in * eqn
x + 0.6x = 1600
1.6x = 1600
x = 1000
then,
y = 0.6*1000
y = 600
the numbers are 1000 and 600
- ∆ABD is right angled hence area:-
There is only one option containing 6x^2 i.e Option D.
Hence without calculating further
Option D is correct
D is true!!
Hope this helped:)
Answer:
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Step-by-step explanation:
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