Question

Help!!!

Answer 1

Answer:

1. 0.82 gram of Ag+

2. 4.79 g of Ag₂O₃S

Explanation:

From the given information:

Total amount of Ag₂O₃S = 2.24 grams

Atomic mass of Ag+ =107.86 g/mole

molar mass of Ag₂O₃S = 295.8  g/mole

∴

The mass of the Silver (Ag) in grams is:

$= Total\ amount \ of \ Ag^+ \times \dfrac{107.86 \ g/mol}{295.8 \ g/mol}$

$=2.24 \times \dfrac{107.86 \ g/mol}{295.8 \ g/mol}$

= 0.82 gram of Ag+

2.

Here, the total amount of Ag₂O₃S = unknown

Atomic mass of Ag+ = 107.86 g/mole

molar mass of Ag₂O₃S = 295.8 g/mole

amount of Ag+  = 1.75 g

∴

The mass of Ag₂O₃S = $Total \ amount \ of \ Ag^+ \times \dfrac{295.8 \ g/mol}{107.86\ g/mol}$

$=1.75 \times \dfrac{295.8 \ g/mol}{107.86\ g/mol}$

= 4.79 g of Ag₂O₃S