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2 years ago

52. In the following reaction, which are the Spectator ions? *

Chemistry

1 answer:

maks197457 [2]2 years ago

5 0

Answer:

nitrate and sodium are spectator ions .The reactions that form an aqueous solution are often a spectator ions.

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What is the initial temperature (°C) of a system that has the pressure decreased by 10 times while the volume increased by 5 tim

Ede4ka [16]

Answer:

300K

Explanation:

Given pressure of the system decreased by 10 times which means $P_{2} =\frac{P_{1} }{10}$

Given the volume of the system increased by 5 times which means $V_{2} =5\times V_{1}$

Given final temperature $T_{2}=150K$

Let the initial temperature be $T_{1}$

We know that PV=nRT

As n and R are constant $\frac{PV}{T}=constant$

$\frac{P_{1}V_{1} }{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}$

$T_{1} =\frac{P_1V_1}{P_2V_2} T_{2}$

$T_{1} =2\times T_{2}$

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3 years ago

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2 years ago

What is the wavenumber of the radiation emitted when a hydrogen

LUCKY_DIMON [66]

Answer: Wavenumber of the radiation emitted is $0.08\times 10^{8}m^{-1}$

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

$E=\frac{hc}{\lambda}$

where,

E = energy of the radiation = $1.634\times 10^{-18}J$

h = Planck's constant = $6.626\times 10^{-34}Js$

c = speed of light = $3\times 10^8m/s$

$\lambda$ = wavelength of radiation = ?

Putting values in above equation, we get:

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$\bar {\nu}=\frac{1}{\lambda}=\frac{1}{12.16\times 10^{-8}}=0.08\times 10^{8}m^{-1}$

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