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MAVERICK [17]
3 years ago
14

Can someone help me please ​

Computers and Technology
1 answer:
Romashka [77]3 years ago
6 0

Answer:

this is more up to you on what you think you are good at and what you need to develop in.

You might be interested in
The requester of sensitive information should not receive access just because of his or her clearance, position, or rank. The re
JulsSmile [24]

Answer:

Need to know

Explanation:

Need to know is a policy or predetermined criterion by which the requester of an information is granted access to the requested information only when a valid need is establish and not just because of his or her clearance, position, or rank.  

7 0
3 years ago
[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

6 0
3 years ago
Design a class named Employee. The class should keep the following information in member variables:
Paha777 [63]

Answer:

Here is the code.

Explanation:

#include <iostream>

#include <cstdlib>

#include <string>

#include <iomanip>

using namespace std;

class Employee

{

private:

string employeeName;

int employeeNumber;

int hireDate;

public:

void setemployeeName(string employeeName);

void setemployeeNumber(int);

void sethireDate(int);

string getemployeeName() const;

int getemployeeNumber() const;

int gethireDate() const;

Employee();

};

void Employee::setemployeeName(string employeeName)

{

employeeName = employeeName;

}

void Employee::setemployeeNumber(int b)

{

employeeNumber = b;

}

void Employee::sethireDate(int d)

{

hireDate = d;

}

string Employee::getemployeeName() const

{

return employeeName;

}

int Employee::getemployeeNumber() const

{

return employeeNumber;

}

int Employee::gethireDate() const

{

return hireDate;

}

Employee::Employee()

{

cout << "Please answer some questions about your employees, ";

}

class ProductionWorker :public Employee

{

private:

int Shift;

double hourlyPay;

public:

void setShift(int);

void sethourlyPay(double);

int getShift() const;

double gethourlyPay() const;

ProductionWorker();

};

void ProductionWorker::setShift(int s)

{

Shift = s;

}

void ProductionWorker::sethourlyPay(double p)

{

hourlyPay = p;

}

int ProductionWorker::getShift() const

{

return Shift;

}

double ProductionWorker::gethourlyPay() const

{

return hourlyPay;

}

ProductionWorker::ProductionWorker()

{

cout << "Your responses will be displayed after all data has been received. "<<endl;

}

int main()

{

ProductionWorker info;

string name;

int num;

int date;

int shift;

double pay;

cout << "Please enter employee name: ";

cin >> name;

cout << "Please enter employee number: ";

cin >> num;

cout << "Please enter employee hire date using the format \n";

cout << "2 digit month, 2 digit day, 4 digit year as one number: \n";

cout << "(Example August 12 1981 = 08121981)";

cin >> date;

cout << "Which shift does the employee work: \n";

cout << "Enter 1, 2, or 3";

cin >> shift;

cout << "Please enter the employee's rate of pay: ";

cin >> pay;

info.setemployeeName(name);

info.setemployeeNumber(num);

info.sethireDate(date);

info.setShift(shift);

info.sethourlyPay(pay);

cout << "The data you entered for this employee is as follows: \n";

cout << "Name: " << info.getemployeeName() << endl;

cout << "Number: " << info.getemployeeNumber() << endl;

cout << "Hire Date: " << info.gethireDate() << endl;

cout << "Shift: " << info.getShift() << endl;

cout << setprecision(2) << fixed;

cout << "Pay Rate: " << info.gethourlyPay() << endl;

system("pause");

return 0;

}

7 0
3 years ago
What is booting as used in computers?​
Sliva [168]

Answer:

the startup process

Explanation:

5 0
3 years ago
Read 2 more answers
If you want to copy data from one cel to another cell that is several rows down in a worksheet, which method should you use?
bogdanovich [222]

copy and paste

so you can keep the data in the current cell and add it to other cells that you want that data in as well

5 0
3 years ago
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