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3 years ago

Please help asap! Will give brainliest! Please read the question then answer correctly! No guessing.

Mathematics

2 answers:

SCORPION-xisa [38]3 years ago

7 0

Answer: A. (0,a)

$f(x) = a \cdot b^x$

$f(0) = a \cdot b^0 = a \cdot 1 = a$

musickatia [10]3 years ago

3 0

Answer:

I think it's B, but I don't really know how to explain it. Please rate this answer 5 stars if it is correct.

Step-by-step explanation:

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In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

Given that:

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

So, the area of given triangle to the nearest square centimetre is:

$Area \approx 1149\ cm^2$

8 0

4 years ago

Megan and Suzanne each have a plant. They track the growth of their plants for four weeks. Whose plant grew at a faster rate, an

CaHeK987 [17]

In science, rate is a quantity measured with respect to another measured quantity. For the data given, we get the rate of each by calculating the slope. We do as follows:

Megan's rate = 12 - 4.5 / 4 -1 = 2.5 inches per week
Suzanne's rate = 11 - 5 / 4-1 = 0.5 inches per week

Therefore, the plant that grew at a faster rate would be Megan’s at 2.5 inches per week.

4 0

3 years ago

Read 2 more answers

Solve 4sin^2 x-3=0 find two values of sinx that satisfy this equation

Leviafan [203]

$4 sin^{2} x-3=0 \\ 4 sin^{2} x=3 \\ sin^{2} x= \frac{3}{4} \\ sinx= \pm \sqrt{ \frac{3}{4} } \\ sinx= \frac{ \sqrt{3} }{2} \ or \ sinx=- \frac{ \sqrt{3} }{2} \\ x= \frac{ \pi }{3} , \ \frac{2 \pi }{3} , \ \frac{4 \pi }{3} , \ \frac{5 \pi }{3}$