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andreyandreev [35.5K]
3 years ago
8

If 4-3(2-x)<10+x what is the greatest possible integer value of x?

Mathematics
2 answers:
Alex3 years ago
5 0

Answer:

4-3(2-x) < 10+x

4 -6 +3x< 10 + x

-2 +3x< 10 +x

2x< 12

x<6

amid [387]3 years ago
4 0

↣ First we solve the Inequality.

4-3(2-x)

4-6+3x     ↣ Distribute -3 in (2-x) for easier in solving.

3x-2

Thus, the answer is x < 6.

↣ Therefore, the <u>greatest</u> possible <u>Integer</u> value of x is 5.

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