Question

If 4-3(2-x)<10+x what is the greatest possible integer value of x?

Answer 1

Answer:

4-3(2-x) < 10+x

4 -6 +3x< 10 + x

-2 +3x< 10 +x

2x< 12

x<6

Answer 2

↣ First we solve the Inequality.

$4-3(2-x)$

$4-6+3x$     ↣ Distribute -3 in (2-x) for easier in solving.

$3x-2$

Thus, the answer is x < 6.

↣ Therefore, the greatest possible Integer value of x is 5.