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goblinko [34]
3 years ago
13

How many squares to shade

Mathematics
1 answer:
slamgirl [31]3 years ago
6 0
You got to shade five squares
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Bob gets paid more in tips when he works more hours at the restaurant. Which is the dependent variable? A. hours worked B. tips
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A. hour worked. . . . . .. .. .. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ..                                                 

4 0
3 years ago
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Choose the equation that best represents the general form of the following expression. x^2/2=7x user: what is the value of "c" i
AlexFokin [52]
X^2/2 = 7x
x^2 = 14x
x^2 - 14x = 0


A quadratic equation is of the form ax^2 + bx + c
Therefore, in 3x^2 + 5x + 7, c = 7
4 0
2 years ago
Which of the following are solutions to the quadratic equation? Check all that
xenn [34]

Step-by-step explanation:

I don't see options but here's the solution

2x²+9x-3=-x²+x

2x²+x²+9x-x-3=0

3x²+8x-3=0

(3x-1)(x+3)=0

Therefore x=⅓ or-3

6 0
2 years ago
The event of walking your dog is A and the event of electing a female as class president is B. If these events are independent e
KengaRu [80]

The value of the probability is 0.54

<h3>How to determine the probability?</h3>

The given parameters are:

P(A) = 0.35

P(B) = 0.54

From the question, we understand that the events are independent.

This means that

P(B|A) = P(B)

Substitute P(B) = 0.54

P(B|A) = 0.54

Hence, the value of the probability is 0.54

Read more about probability at:

brainly.com/question/11234923

#SPJ1

3 0
2 years ago
The distribution of the test statistic for analysis of variance is the F-distribution. true or false
lubasha [3.4K]

Answer:

True. See explanation below

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

If we assume that we have k groups and on each group from j=1,\dots,k we have k individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2  

SS_{between=Treatment}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}  

The degrees of freedom for the numerator on this case is given by df_{num}=k-1 where k represent the number of groups.  

The degrees of freedom for the denominator on this case is given by df_{den}=df_{between}=N-k.  

And the total degrees of freedom would be df=N-1

And the we can find the F statistic F=\frac{MSR}{MSE}

8 0
3 years ago
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