The car has gravitational potential energy (Eg)
Eg = mgh
Eg = (53kg) (9.81N/kg) (14m)
Eg = 7 279.02 J
Answer:
3. 560W
Explanation:
First we calculate the work required for the 700N weigh student to climb up by 8 meters. Work is force times distance
W = Fs = 700 * 8 = 5600J
The average power is defined as the rate of energy expended over a unit of time. In order words, work divided by time duration
P = W/t = 5600 / 10 = 560 W
Well if it was traveling for an hour then the answer is 8 miles.
Answer:
F = 24 N
Explanation:
In this exercise we have a bar l = 100 m with a center of gravity x = 4 m, which force is needed to lift it from the other end
Let's use the rotational equilibrium relationship, where we consider the counterclockwise rotations as positive and fix the reference system at the point closest to the center of gravity
∑ τ = 0
F l -x W = 0
F = 
let's calculate
F =
4/100 600
F = 24 N