Answer:
a) x = (0.0114 ± 0.0001) in
, b) the number of decks is 5
Explanation:
a) The thickness of the deck of cards (d) is measured and the thickness of a card (x) is calculated
x = d / 52
x = 0.590 / 52
x = 0.011346 in
Let's look for uncertainty
Δx = dx /dd Δd
Δx = 1/52 Δd
Δx = 1/52 0.005
Δx = 0.0001 in
The result of the calculation is
x = (0.0114 ± 0.0001) in
b) You want to reduce the error to Δx = 0.00002, the number of cards to be measured is
#_cards = n 52
The formula for thickness is
x = d / n 52
Uncertainty
Δx = 1 / n 52 Δd
n = 1/52 Δd / Δx
n = 1/52 0.005 / 0.00002
n = 4.8
Since the number of decks must be an integer the number of decks is 5
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Answer:
Explanation:
if its squares count the squares els messure it i think
Answer:
The x-component of 
is 56.148 newtons.
Explanation:
From 1st and 2nd Newton's Law we know that a system is at rest when net acceleration is zero. Then, the vectorial sum of the three forces must be equal to zero. That is:
(1)
Where:
, 
, 
- External forces exerted on the ring, measured in newtons.
- Vector zero, measured in newtons.
If we know that ![\vec F_{1} = (70.711,70.711)\,[N]](https://tex.z-dn.net/?f=%5Cvec%20F_%7B1%7D%20%3D%20%2870.711%2C70.711%29%5C%2C%5BN%5D)
, ![\vec F_{2} = (-126.859, 46.173)\,[N]](https://tex.z-dn.net/?f=%5Cvec%20F_%7B2%7D%20%3D%20%28-126.859%2C%2046.173%29%5C%2C%5BN%5D)
, 
and ![\vec O = (0,0)\,[N]](https://tex.z-dn.net/?f=%5Cvec%20O%20%3D%20%280%2C0%29%5C%2C%5BN%5D)
, then we construct the following system of linear equations:
(2)
(3)
The solution of this system is:
, 
The x-component of is 56.148 newtons.
Answer:
The difference between the velocity graph made walking at a steady rate means that its the same value in time, that means there's no slope on the graph, so its acceleration is 0
On the other hand, if the velocity is increasing with time, the slope of the graph becomes positive, which means that the acceleration of the particle is positive.
