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SCORPION-xisa [38]
3 years ago
7

Find the angle of incidence at which a light beam traveling from a medium having the index of refraction n1 = 2.7 to another med

ium having the index of refraction n2 = 1.6 suffers a total internal reflection.
Physics
1 answer:
luda_lava [24]3 years ago
7 0

Answer:

The angle of incidence at which total internal reflection takes place will be equal to \Theta _c=36.34^{\circ}

Explanation:

We have given that light is traveling from a medium  of refractive index x 2.7 to a medium of refractive index 1.6

So refractive index of first medium n_1=2.7 and n_2=1.6

We have to find the angle of incidence for total internal reflection

For total internal reflection

n_1sin\Theta _c=n_2sin90^{\circ}

\Theta _c=sin^{-1}\frac{n_2}{n_1}

\Theta _c=sin^{-1}\frac{1.6}{2.7}

\Theta _c=36.34^{\circ}

So the angle of incidence at which total internal reflection takes place will be equal to \Theta _c=36.34^{\circ}

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