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V125BC [204]
3 years ago
7

If u guess a number 1-50 and get it right I will give u branliest

Mathematics
2 answers:
Reptile [31]3 years ago
7 0

Answer:

is it 8 lhh

Step-by-step explanation:

gulaghasi [49]3 years ago
5 0

My guess is 50 Or 30

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Will mark you as brainliest. If your good with polynomials.
kobusy [5.1K]
To solve/simplify this all you have to do is group like terms (the x^2's with each other, the x's with each other, and the normal numbers, -8)

14x^2-8+5x-6x^2+2x

group the x^2 (add 14x^2 to -6x^2)

8x^2-8+5x+2x

group the x's together (add 5x and 2x together)

8x^2+7x-8

Your answer will be d) 8x^2+7x-8



4 0
3 years ago
A boat costs $19,200 and decreases in value by 12% per year. How much will the
fomenos
Find 10% of $19,200 = 1,920
Find 2% of $1,920 = 384
12% = $2,304
19,200 - 2,304 = 16,896 (year 1)
Repeat this until you have your 5th year :)
4 0
3 years ago
Which of the following graphs represents the solution set for 7(4x – 1 ) + 6x > –279? PLEASE HELP
Luda [366]
First, solve the inequality:
7(4x - 1 ) + 6x \ \textgreater \  -279\\
28x-7+6x\ \textgreater \ -279\\
34x\ \textgreater \ -272\\
x\ \textgreater \ -8
Since x is <u>greater than</u> -8, you have the arrow point up the graph towards the positive side starting at -8.
Since it's greater than but not equal to -8, the circle is open.

Thus your graph is D.
3 0
3 years ago
5x + 2 y = 7<br> 4x + y = 8
dsp73
4y.
Is the answer
Hope this helps
8 0
2 years ago
Total profit P is the difference between total revenue R and total cost C. Given the following​ total-revenue and​ total-cost fu
gavmur [86]

Answer:

The profit function is:

P(x)=-x^2+1280x-3300

The maximum value is 406, 300 occurring when x = 640.

Step-by-step explanation:

The revenue function is:

R(x)=1300x-x^2

And the cost function is:

C(x)=3300+20x

Then the total profit function will be:

P(x)=R(x)-C(x)=(1300x-x^2)-(3300+20x)=-x^2+1280x-3300

This is a quadratic function.

Therefore, the maximum value of the total profit will occur at its vertex point.

The vertex of a quadratic is given by:

\displaystyle \Big(-\frac{b}{2a}, f\Big(-\frac{b}{2a}\Big)\Big)

In this case, a = -1, b = 1280, and c = -3300.

Then the point at which the maximum profit occurs is at:

\displaystyle x=-\frac{1280}{2(-1)}=640

And the maximum profit will be:

P(640)=-(640)^2+1280(640)-3300=406300

5 0
3 years ago
Read 2 more answers
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