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lesya692 [45]
3 years ago
14

Find an ordered pair of 5x + y = 3

Mathematics
1 answer:
Rufina [12.5K]3 years ago
7 0

Answer:

Step-by-step explanation:

Find an ordered pair that satisfies the equation 5x + y = 3.  

There are infinitely many ordered pairs that satisfy this equation.

If we were to choose y = 0, then 5x = 3, and x = 3/5, leading to the ordered pair (3/5, 0).

If we were to choose x = 1, then 5(1) + y = 3, or y = -2.  The ordered pair would be (1, -2).

And so on.

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A family spends 1⁄10 of its annual income for housing, 1⁄4 for food and clothing, 1⁄5 for general expenses, and 2⁄15 for enterta
tankabanditka [31]
In order to make the whole problem easier, you would have to get all the numbers to have the same denominator which would be 60.

1/10 * 6 = 6/60
1/4 * 15 = 15/60
1/5 * 12 = 12/60
2/15 * 4 = 8/60

Now that all the numbers have the same denominator, you would add them to get 41/60.
In conclusion, the answer would be D.
5 0
3 years ago
Sides AB and BC are congruent. If BAC =22 , then ABC = °.
lina2011 [118]
<span>ABC =22° because AB and BC are congruent
</span>
7 0
3 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
Use your knowledge of similar triangles to explain why the construction in the image divides the line segment into equal parts.
strojnjashka [21]

Answer:

This image show how to divide a given line segment into a number of equal parts by using a compass and  ruler. First, draw the line AB. Secondly, draw a line above and divide into 5 equal distances to make a line AC. Third, using a compass by getting the distance of point C and B to be equal in the distance of point A and D, also getting the distance of point C to A to be equal to point B and D, then to make the Line DB. Finally divide into 5 equal parts by compass.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
P+q=1 and pq=-20. What are the values of p and q?​
andrey2020 [161]

Answer:

Step-by-step explanation:

5, -4

5-4=1

5(-4)=-20

6 0
2 years ago
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