2x+3(5-x)-12=4(x+2)
Distribution property:
2x+15-3x-12=4x+8
Add like terms:
-1x+3=4x+8
Add 1x to both sides:
3=5x+8
Subtract 8 from both sides:
-5=5x
Divide by 5 on both sides to get x by itself:
x= -1
We can put 0, 1 and 2 for x then y will be :
0, -4 and -8
![\binom{0}{0} \: \: \: \: \: \binom{1}{ - 4} \: \: \: \: \: \binom{2}{ - 8}](https://tex.z-dn.net/?f=%20%5Cbinom%7B0%7D%7B0%7D%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Cbinom%7B1%7D%7B%20-%204%7D%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Cbinom%7B2%7D%7B%20-%208%7D%20)
good luck
For number 24, x is equals to 10. It's given that the two triangles are congruent, meaning the angles are congruent too. So, angle A is equals to angle D. Angle A is equals to x+10 and angle D equals to 2x. So we make the two equations equal to each other, x+10=2x, we subtract x from both sides and we get x=10. Remember to replace x with 10 and solve it. The angle would be 20°
For number 25, it's the same thing but we are using sides this time. We make both equations equal to each other and solve for z. 3z+2=z+6, subtract z from both sides and we get 2z+2=6, now we subtract two from both sides and we are left with 2z=4, we are not done yet. We have to isolate z, so we divide both sides by 2 since z is being multiplied by 2, and we end up with z = 2
Remember to replace z with 2, the side would be 8.
I hope this helps. Sorry for the long answer and being late.
YOU'RE WELCOME :D
8,800 more meters if I an reading it right
Answer: Choice C
![x < -2 \text{ or } x \ge 4](https://tex.z-dn.net/?f=x%20%3C%20-2%20%5Ctext%7B%20or%20%7D%20x%20%5Cge%204)
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Reason:
The portion on the left represents
because of the open circle at -2 and shading pointing to the left. This represents all numbers smaller than -2.
The portion on the right represents all values that are 4 or larger; hence
. Note the use of a closed circle at 4 to include this value.
We connect those two inequalities with the keyword "or" because x can only pick one of those options, but not both at the same time.