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jenyasd209 [6]
3 years ago
12

Describe the solution in words to the inequality 4

Mathematics
1 answer:
MArishka [77]3 years ago
4 0

Answer:

Full problem or picture?

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Find the area.<br> 13 mm<br> 26 mm<br> 15 mm<br> 32 mm<br><br><br><br> PLS HELPPP ‍♀️‍
Inessa [10]

Answer:

area=20x13x26x15x32=formula is +ALL20X13=260x26=5720x15x32480 is yours you play ff

3 0
3 years ago
Explain why g(x)= {sin π/x if =0, 1 if x=0 , is not continuous a x=0
stepladder [879]

Answer:

\lim_{x\rightarrow 0}g(x) does not exist.

D is correct.

Step-by-step explanation:

We are given,

g(x)=\left\{\begin{matrix} \sin\left ( \dfrac{\pi}{x} \right )& \ \ \ if\ \ x\neq 0\\ 1& \ \ \ if\ \ x\neq 0\end{matrix}\right.

For continuous function, LHL=RHL=f(0)

Using squeeze theorem,

If g(x)\leq f(x)\leq h(x)

then \lim_{x\rightarrow a}g(x)\leq \lim_{x\rightarrow a}f(x)\leq \lim_{x\rightarrow a}h(x)

As we know

-1\leq \sin\left ( \dfrac{\pi}{x} \right )\leq 1

Apply Limit both sides

\lim_{x\rightarrow 0}(-1)\leq \lim_{x\rightarrow 0}\sin\left ( \dfrac{\pi}{x} \right )\leq \lim_{x\rightarrow a}1

\lim_{x\rightarrow 0}(-1)=-1

\lim_{x\rightarrow 0}(1)=1

-1\neq 1

LHL\neq RHL=g(0)

If LHL\neq RHL then limit does not exist.

Hence, \lim_{x\rightarrow 0}g(x) does not exist.

D is correct.

7 0
3 years ago
What is 14% of 60 million?
babunello [35]
So 14% changes to 0.14

Multiply 60 million x 0.14= 8,400,000
5 0
3 years ago
Antoine wants to get a subscription to a local library. There are two libraries, each of which charges a monthly subscription fr
frozen [14]

Answer:

the first one is B and the second one is A

Step-by-step explanation:

I guessed and I got it right

5 0
3 years ago
Read 2 more answers
Please hurry help thank u
jenyasd209 [6]

Answer:

choice 4

similar polygons have to compared at a similar level. so choice 4

3 0
3 years ago
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