The exponential equation of the model is A(t) = 2583 * 0.88^t and the multiplier means that the number of new cases in a week is 88% of the previous week
<h3>The function that models the data</h3>
The given parameters are:
New, A(t) = 2000
Rate, r = 12%
The function is represented as:
A(t) = A * (1 - r)^t
So, we have:
2000 = A * (1 - 12%)^t
This gives
2000 = A * (0.88)^t
2 weeks ago implies that;
t = 2
So, we have:
2000 = A * 0.88^2
Evaluate
2000 = A * 0.7744
Divide by 0.7744
A = 2583
Substitute A = 2583 in A(t) = A * 0.88^t
A(t) = 2583 * 0.88^t
Hence, the exponential equation of the model is A(t) = 2583 * 0.88^t
<h3>The interpretation of the multiplier</h3>
In this case, the multiplier is 88% or 0.88
This means that the number of new cases in a week is 88% of the previous week
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Answer:
42x -27
Step-by-step explanation:
we apply distributive property:
7(6x – 4) + 1
7*6x - 7*4 +1
42x - 28 +1
42x -27
D(e^(In(x))^2)/dx = 2 In(x) * 1/x * e^(ln(x))^2 = (2e^(ln(x))^2 * In(x)) / x
Answer:
2sin(3θ) - √3 = 0
Step-by-step explanation:
sin(3θ) = √3/2
3θ = π/3 + 2kπ or 2π/3 + 2kπ, k = 0, ±1, ±2, ±3,...
θ = π/9 + 2kπ/3, 2π/9 + 2kπ/3
If k = 0, we get θ = π/9, 2π/9
If k = 1, we get θ = 7π/9, 8π/9
If k = 2, we get θ = 13π/9, 14π/9
Other values of k give values of θ lying outside of the interval [0, 2π).
The Corectttttt Answerrrrr is C
