Answer:
0.077994
Step-by-step explanation:
Given that the owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club.
![H_0: Mean = 30\\H_a: Mean >30](https://tex.z-dn.net/?f=H_0%3A%20Mean%20%3D%2030%5C%5CH_a%3A%20Mean%20%3E30)
(Right tailed test)
Sample size = ![n=250](https://tex.z-dn.net/?f=n%3D250)
Sample mean = 30.45
Mean difference =![30.45-30=0.45\\](https://tex.z-dn.net/?f=30.45-30%3D0.45%5C%5C)
Sample std dev s = 5
Sample std error = ![\frac{5}{\sqrt{n} } =\frac{5}{\sqrt{250} } \\=0.3163](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B%5Csqrt%7Bn%7D%20%7D%20%3D%5Cfrac%7B5%7D%7B%5Csqrt%7B250%7D%20%7D%20%5C%5C%3D0.3163)
Test statistic = Mean diff/std error = ![=\frac{0.45}{0.3163} =1.423](https://tex.z-dn.net/?f=%3D%5Cfrac%7B0.45%7D%7B0.3163%7D%20%3D1.423)
Since population std deviation is not know we use t test
p value = ![0.077994](https://tex.z-dn.net/?f=0.077994)
300.
Steps:
27x100 = 2700
12x300=3600
3600+2700=6300
Answer:
Answer choice B
Step-by-step explanation:
When you factor the equation, 12 only has 6x2 to equal the -12x. This means that you'll factor it into (3x-6)(x-2). When you set either of these equal to 0, the x value is 2.
Answer: 1/6
Step-by-step explanation:
A die has 6 numbers which are 1, 2, 3, 4, 5 and 6.
Odd numbers in a die = 1, 3 and 6
Numbers greater than 4 = 5 and 6
Probability of rolling an odd number = 3/6 = 1/2
Probability of rolling a number greater than 4 = 2/6 = 1/3
We then multiply both values gotten. This will be:
= 1/2 × 1/3
= 1/6
Therefore, the probability of rolling an odd number the first time and a number greater than 4 the second time is 1/6.
Answer:
There is no solution
Step-by-step explanation:
-4(x+3)=16-4x
expand
−4x−12=16−4x
cancel out
−12=16
because −12=16 is false there is no solution.
Hope this helps :)