In a circle, the measure of an inscribed angle is half the measure of the intercepted arc ⇒
arc BAD = 2*∠BCD = 2*104 = 208°
arc BCD = 360 - arc BAD = 360 - 208 = 152°
Look at one of the vertices of the heptagon where two squares meet. The angles within the squares are both of measure 90 degrees, so together they make up 180 degrees.
All the angles at one vertex must clearly add up to 360 degrees. If the angles from the squares contribute a total of 180 degrees, then the two remaining angles (the interior angle of the heptagon and the marked angle) must also be supplementary and add to 180 degrees. This means we can treat the marked angles as exterior angles to the corresponding interior angle.
Finally, we know that for any convex polygon, the exterior angles (the angles that supplement the interior angles of the polygon) all add to 360 degrees (recall the exterior angle sum theorem). This means all the marked angles sum to 360 degrees as well, so the answer is B.
You need to find the negative reciprocal of the rate of change. In this case, your rate of change is 4/3. The negative reciprocal would be -3/4...
so basically, just write an equation w -3/4 as the rate of change. For example: y= -3/4x + 4
Answer:
1/8
Step-by-step explanation:
first multiply 2 x 2 and you get 4
then multiply 2x2x2x2x2 and you get 32
simplify 4/32
4 divided by 4 = 1
32 divided by 4 = 8
1/8
I hope this is clear!
Answer:
<em>Answer is option d</em><em>)</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>-4</em><em> </em><em>,</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>-3</em>
Step-by-step explanation:
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