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PSYCHO15rus [73]
3 years ago
14

What is the mean absolute deviation of the data set 0, 0, 1, 2, 3, 3, 8, 9, 10

Mathematics
1 answer:
crimeas [40]3 years ago
8 0
0+0+1+2+3+3+8+9+10=36
36/9
/ = divide
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Find the vertex, focus, directrix, and focal width of the parabola. (5 points)
Anarel [89]

\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf -\cfrac{1}{20}x^2=y\implies \cfrac{x^2}{-20}=y\implies x^2=-20y\implies (x-0)^2=-20(y-0) \\\\\\ (x-\stackrel{h}{0})^2=4(\stackrel{p}{-5})(y-\stackrel{k}{0})

something noteworthy is that the squared variable is the "x", thus the parabola is a vertical one, the "p" value is negative, so is opening downwards, and the h,k is pretty much the origin,

vertex is at (0,0)

the focus point is "p" or 5 units down from there, namely at (0, -5)

the directrix is "p" units on the opposite direction, up, namely at y = 5

the focal width, well, |4p| is pretty much the focal width, in this  case, is simply yeap, you guessed it, 20.

8 0
3 years ago
6 1/2 divided by 3/4 pls someone help ASAP
e-lub [12.9K]

Answer:

Its basically asking 6.50 / .75 which is 8.6 or you can round it to 8.7

Step-by-step explanation:

8 0
3 years ago
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since left and right (sides) goes up and down


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Y=7x+1

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b) (3,?)
    y=7(3)+1
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6 0
3 years ago
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Please help me i need to study it
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Answer:

360

Step-by-step explanation:

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